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Licemer1 [7]
3 years ago
6

PLEASE HELP!!!!!

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer:

Equation: 30=2(x-2)+2(2x+3)

x:\frac{14}{3}

Step-by-step explanation:

By definition, the perimeter of a figure can be calculated by adding the lenghts of its sides.

Knowing this, you can write the following equation:

P=2(x-2)+2(2x+3) <em> [Equation 1]</em>

According to the data given in the exercise, the perimeter in feet of the fighter is:

P=30

Therefore, you can substitute this values into<em> [Equation 1]:</em>

30=2(x-2)+2(2x+3)

Finally, you must solve for "x" in order to find its value. This is:

30=6x+2\\\\30-2=6x\\\\\frac{28}{6}=x\\\\x=\frac{14}{3}

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Answer:

\huge\boxed{13}

Step-by-step explanation:

= 2k - x

Given that k = 9, x = 5

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\rule[225]{225}{2}

Hope his helped!

<h3>~AH1807</h3>
8 0
3 years ago
The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

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Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

P_1 = 0.36 - 0.2 = 0.16

At the same way, the probability P_2 that he must stop at the second signal but not at the first one can be calculated as:

P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

7 0
3 years ago
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Answer:

between 78 and 102 texts and more than 78 text messages.

Step-by-step explanation:

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7 0
4 years ago
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Answer:

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