<span>ALPO4 can be broken up into AL/P/O4.
There is one AL mole, one P mole, and four O moles. Together, that is a total of six moles -- 1 + 1 + 4 = 6. You can find the moles for each section by breaking the atoms up by type. There are 4 O because the number 4 follows the O. There are none in front of AL or P, so they are singular.</span>
<span> Na2CO3 + 2HCl = CO2 + H2O + 2NaCl
this is the double displacement reaction
</span><span>2 Na(+) + CO3(-2) + 2H(+) + 2Cl(-) ------> 2Na(+) + 2 Cl(-) + H2O + CO2
</span>2Na+ and 2Cl- are the spectator ions as they appear on the both sides of equation :
so the net ionic equation can be written as :
CO3(-2) + 2H(+) -------------> <span>H2O + CO2</span>
Answer:
Therefore, the value of K_{p} is 2 \times 10^{9} and value of \Delta G^{o} is -53.2 kJ/mol.
Explanation:
Answer:
In the third tube, the concentration is 0.16 ug/mL
Explanation:
In the first step, the solution is diluted by 5. Then, the concentration will be
20 ug/mL / 5 = 4 ug/mL
Then, in the second step this 4 ug / ml solution is diluted by a factor of five again:
4 ug /ml / 5 = 0.8 ug/mL
This solution is then diluted again by 5 and the concentration in the third tube will be then:
0.8 ug/mL / 5 = <u>0.16 ug/mL </u>
<u />
Another way to calculate this is to divide the original concentration by the dilution factor ( 5 in this case) elevated to the number of dilutions. In this case:
Concentration in the third tube = 20 ug/mL / 5³ = 0.16 ug/mL
The electron dot diagram tells
us about how many electrons are being shared between atoms. Also, the number of
valence electron to be shared corresponds to the group number the element
belongs. Say for example H2O, hydrogen has one valence electron and oxygen has
two valence electrons.
