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Scrat [10]
3 years ago
5

Chang and Carlotta solve this problem in two different ways. You have $50 in your bank account. You make $8 per hour mowing lawn

s. How many hours must you mow lawns to have a total of $130 in your account?
Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

8 hours

Step-by-step explanation:

You can solve this problem by inputting the values into an equation. Here is the equation below:

50 + 8x = 130

Lets solve for x. First you subtract 50 from 130.

1) 8x = 130 - 50

2) 8x = 80

Next, you divide 80 by 8 to get x by itself.

1) x = \frac{80}{8}

2) x = 10

This means that you must mow lawns for 8 more hours to get a total of $130 in your bank account.

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HELP ME PLSSSSSSSSSSS
Trava [24]

Answer:

8

Step-by-step explanation:

I believe that the answer is 8

8 0
2 years ago
In the diagram below, triangle abc ~ triangle dec . What is the value of x? A. 28 b. 24 c. 22 d. 26
Lesechka [4]

Answer:

Option A.

Step-by-step explanation:

From the figure attached,

Given : ΔABC ~ ΔDEC

By the property of similarity,

"Corresponding sides of the similar triangles are proportional"

\frac{\text{AB}}{ED}=\frac{BC}{EC}=\frac{AC}{DC}

Since, \frac{\text{AB}}{ED}=\frac{AC}{DC}

\frac{42}{6}=\frac{x}{(32-x)}

6x = 42(32 - x)

6x = 1344 - 42x

6x + 42x = 1344

48x = 1344

x = \frac{1344}{48}

x = 28 units

Therefore, Option (A). x = 28 units will be the answer.

4 0
3 years ago
PLEASE HELP
Vlad [161]
Do you need the answer now ?
3 0
2 years ago
An arched drainage culvert can be modelled by the function:
Zanzabum

Substitute 136.5 for y.

136.5=\frac{x(191-x)}{60}

8190=x(191-x)

8190=191x-x^{2}

x^{2} -191x+8190=0

Compare this equation with ax^{2} +bx+c=0

a = 1, b = - 191, c = 8190

x=\frac{-b+\sqrt{b^{2}-4ac } }{2} or

x=\frac{-b-\sqrt{b^{2}-4ac } }{2}

x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2} or

x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}

x=\frac{191+\sqrt{36481-32760 } }{2} or

x=\frac{191-\sqrt{36481-32760 } }{2}

x=\frac{191+\sqrt{3721 } }{2} or

x=\frac{191-\sqrt{3721 } }{2}

x=\frac{191+61}{2} or

x=\frac{191-61}{2}

x=\frac{252}{2} or

x=\frac{130}{2}

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = \sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}

= \sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}

= 126 - 65

= 61

Hence, width of the air space is 61m.



5 0
3 years ago
I need some help pls
Nimfa-mama [501]
Answer is A, basically using the Pythagorean theorem but in a slightly different way, should still get you the same answer.
4 0
2 years ago
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