The equation 116 = -7(4 - 2p) + 4p is equivalent to which of the following?

Mathematics

1 answer:

Alexxx [7]3 years ago

4 0

Answer:

Step-by-step explanation:

You distribute -7 into (4-2p) and then combine like terms to get 116=-28-18p

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The length of a rectangle is three more than twice the width. The perimeter is 96. What are the dimensions?

SIZIF [17.4K]

Answer:

Width =15

Length =33

Step-by-step explanation:

Take width as x

And length as 2x+3

Perimeter as 96

Formula of the perimeter of a rectangle is 2l+2w

X+×+2×+3+2×+3=96

6x+6=96

6x=96-6

6×=90

X=15

Width =x and x =15 so width =15 while length =33

7 0

3 years ago

3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls

tatuchka [14]

Answer:

$x=\frac{13}{2}, y=\frac{51}{4}$

Step-by-step explanation:

$We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}$

$Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}$