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Crazy boy [7]
3 years ago
8

A brand new car is $22,000 and its value depreciates 7% each year. How many years will it take for your car to be $10,000? Round

to the nearest tenth.
Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

.200 because 22,000 % by 7 is 1540 which you divide by 10,000

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Pls Help! John wants to prove ABC = to DEF. He Knoes AB = DE and AC = DF. With Screenshot
matrenka [14]

Answer:

\angle A \cong \angle D

Step-by-step explanation:

The Side-Angle-Side method cana only be used when information given shows that an included angle which is between two sides of a ∆, as well as the two sides of the ∆ are congruent to the included side and two sides of the other ∆.

Thus, since John already knows that \overline{AB} \cong \overline{DE} and \overline{AC} \cong \overline{DF}, therefore, an additional information showing that the angle between \overline{AB} and \overline{DE} in ∆ABC is congruent to the angle between \overline{AC} and \overline{DF} in ∆DEF.

For John to prove that ∆ABC is congruent to ∆DEF using the Side-Angle-Side method, the additional information needed would be \angle A \cong \angle D.

See attachment for the diagram that has been drawn with the necessary information needed for John to prove that ∆ABC is congruent to ∆DEF.

7 0
2 years ago
$5,000 is invested at 3% interest.
adell [148]
5000*0.03+0.05x=275
Solve for x
X=2500
The answer is b
4 0
3 years ago
Read 2 more answers
Oliver earns $93 per week mowing lawns in his neighborhood. Which expression can be used to show how much money he earns in 6 we
ElenaW [278]
1 week  = $93
6 weeks = $93 x 6 
6 weeks = $558
6 0
3 years ago
78+22=22+78<br> (16+4)+11=(11+4)+16<br> (12+8)+9=(9+8)+12
Ksju [112]
344444444444444444444444
4 0
3 years ago
The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric
Papessa [141]
Let X denote the number of minutes spent brushing his teeth, and let \mu be the mean and \sigma the standard deviation for this distribution.

\mathbb P(X

The z-score corresponding to this probability is approximately z=-0.2533, which means

\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1

Next, (note the sign change)

\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98

The corresponding z-score is approximately z=2.0538, so you have

\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2

Solving the two equations for \mu and \sigma, you'll find that the mean is approximately \mu=1.1098 and the standard deviation is approximately \sigma=0.4334.
7 0
3 years ago
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