Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
I can't be entirely sure what you want to "do" about the slope,
but here is how to FIND it if you have the line on the graph:
-- You pick two points on the graph line.
-- Find the difference in 'y' between the two points.
-- Find the difference in 'x' between the two points.
-- The slope of the line between the two points is
(the difference in 'y')
divided by
(the difference in 'x') .
-- If the line on the graph is a straight line, then
the slope is the same everywhere on it.
Complementary angles always equal 90°
So here is how to find what mCYD + mFZE equal
mCYD + mFZE + mAXB
mCYD + mFZE + 36° = 90°
Subtract
mCYD + mFZE = 54°
Greetings! Hope this helps!
Answer
3 + 2h = 7
-3 -3
2h = 4
/2 /2
h = 2
Have a good day!
_______________
A brainliest would help tons! :D
