Answer:
- square: 9 square units
- triangle: 24 square units
Step-by-step explanation:
Using a suitable formula the area of a polygon can be computed from the coordinates of its vertices. You want the areas of the given square and triangle.
<h3>Square</h3>
The spreadsheet in the first attachment uses a formula for the area based on the given vertices. It computes half the absolute value of the sum of products of the x-coordinate and the difference of y-coordinates of the next and previous points going around the figure.
For this figure, going to that trouble isn't needed, as a graph quickly reveals the figure to be a 3×3 square.
The area of the square is 9 square units.
<h3>Triangle</h3>
The same formula can be applied to the coordinates of the vertices of a triangle. The spreadsheet in the second attachment calculates the area of the 8×6 triangle.
The area of the triangle is 24 square units.
__
<em>Additional comment</em>
We have called the triangle an "8×6 triangle." The intention here is to note that it has a base of 8 units and a height of 6 units. Its area is half that of a rectangle with the same dimensions. These dimensions are readily observed in the graph of the vertices.
His mistake was adding 12+2 when he was supposed to subtract.
C. 4.45 cm. you take the circumference and divide it by pi to find the diameter
Answer:
(64+320π) cm^3
Step-by-step explanation:
The volume of a cube is the length*width*height, so
the volume of this cube is 4*4*4=64 cm^3
The volume of a cylinder is the base*height
The base of a cylinder is the area of a circle, which is π*the radius of the circle squared
The diameter of the circle base is 16, and the radius is half the diameter, so it is 16/2=8.
The area of the base of the cylinder is π8^2=64π
Now, multiply the base by the height, 5
64π*5=320πcm^3
We now have the volume of the cube and the volume of the cylinder, so now we just add them:
(64+320π) cm^3
Sec t (theta) - 2 = 0
sec t = 2
1/ cos t = 2
cos t = 1/2
Answer:
t = π / 3 + 2 k π , or : t = 5 π / 3 + 2 kπ,
k ∈ Z