Answer:
348
Step-by-step explanation:
Answer:
147.5 km and 64.4 km
Step-by-step explanation:
a=120 km
b=70 km
β=28 degrees (
∘)
b^2=(a^2)+(c^2)−2ac*cosβ
70^2
=(120^2
)+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )
(c^2
) −211.907c+9500=0
note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use
p=1;q=−211.907;r=9500
D=(q^2
) −4pr=(211.907^2
)−4⋅1⋅9500=6904.75561996
D>0
=
(−q± 
)/2p=(211.91±
)/2
=105.95371114±41.5474295834
(
−147.501140726)(
−64.4062815596)=0
=147.501140726
=64.4062815596
Answer: 0
Step-by-step explanation:
h ( t ) = − 2 t ^2 + 10 t
h = height of ball above the ground
t = time, seconds after ball was kicked
Height of ball at the time it is kicked?
At the time ball is kicked, time (t) = 0
Therefore,
h ( t ) = − 2 t ^2 + 10 t
h( 0) = - 2(0)^2 + 10(0)
h = 0 + 0
h = 0
The ball was the on the grounf at the time it was kicked.
log(4) + log(2) - log(5)
= log(2²) + log(2) - log(5)
= 2 log(2) + log(2) - log(5)
= 3 log(2) - log(5)
= log(2³) - log(5)
= log (2³/5)
= log (8/5)
= log (1.6) = 0.2041... (rounded)
