The following are the ages of 13 history teachers in a school district. 24, 27, 29, 29, 35, 39, 43, 45, 46, 49, 51, 51, 56 Notic
pishuonlain [190]
The five-number summary and the interquartile range for the data set are given as follows:
- Interquartile range: 50 - 29 = 21.
<h3>What are the median and the quartiles of a data-set?</h3>
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference between the third quartile and the first quartile.
In this problem, we have that:
- The minimum value is the smallest value, of 24.
- The maximum value is the smallest value, of 56.
- Since the data-set has odd cardinality, the median is the middle element, that is, the 7th element, as (13 + 1)/2 = 7, hence the median is of 43.
- The first quartile is the median of the six elements of the first half, that is, the mean of the third and fourth elements, mean of 29 and 29, hence 29.
- The third quartile is the median of the six elements of the second half, that is, the mean of the third and fourth elements of the second half, mean of 49 and 51, hence 50.
- The interquartile range is of 50 - 29 = 21.
More can be learned about five number summaries at brainly.com/question/17110151
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Answer: it will take 13.3 years
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 6000
A = 10000
r = 4% = 4/100 = 0.04
n = 12 because it was compounded 12 times in a year.
Therefore,.
10000 = 6000(1 + 0.04/12)^12 × t
10000/6000(1 + 0.0033)^12t
1.67 = 1.0033^12t
Taking log to base 10 of both sides, it becomes
Log 1.67 = 12tLog 1.0033
0.223 = 12t × 0.0014
0.223 = 0.0168t
t = 0.223/0.0168
t = 13.3 years
Answer:1/32
Step-by-step explanation:
Answer:
Step-by-step explanation:
is pretty simple
292,000/100=2,920
Answer:
yellow
Step-by-step explanation:
