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3 years ago

7

What is the answer to this problem

1 answer:

Crank3 years ago

6 0

Answer:

B: 4x + 5y = -20; if x = 0, y = -4; if y = 0, x = -5 This matches the graph

Step-by-step explanation:

One way of doing this problem is to find the actual x- and y-intercepts of each of the four given functions, and then to compare the results to the graph.

A: 4x - 5y = 20; if x = 0, y = -4; if y = 0, x = 5 Does not match graph

B: 4x + 5y = -20; if x = 0, y = -4; if y = 0, x = -5 This matches the graph

C: 5x - 4y = 20; if x = 0, y = -5; Does not match graph

D: 5x + 4y = -20; if x = 0, y = -5; Does not match graph

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we have

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see the attached figure to better understand the problem

we know that

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and

the area of the triangle is equal to

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in this problem

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we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

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Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

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Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

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Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

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therefore

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Step $6$

<u>Find the area of the triangle</u>

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in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

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