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AnnZ [28]
3 years ago
12

Can u help me wit the answer?? Plz???

Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0
Average weight is when you add up all the weight and divide by the number of objects

if you count the number of x's you will see that you have 10 sandwiches
now add up all the weight

1/8 +1/8+ 1/4+1/4+1/4+1/4+ 3/8+ ....

once you have total weight, divide that number by 10
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Please help with b) and c)
rewona [7]
For b it is A,M and T
For C it is 0%
6 0
2 years ago
The number of events is 29​, the number of trials is 298​, the claimed population proportion is​ 0.10, and the significance leve
Nina [5.8K]

Answer:

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

\hat p=\frac{29}{298}=0.0973 estimated proportion

p_o=0.1 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0
2 years ago
PLEASE HELP ME FIGURE OUT WHICH ONE I GOT WRONG, TYSMM :)
otez555 [7]

Answer:

da one in the middle and i do relize this is a test becuse i just took it.

Step-by-step explanation:

6 0
3 years ago
I really don't get this....
rewona [7]
Seeing you don't have a graphing calculator, use the web, there are many websites dedicated to different calculators
5 0
2 years ago
imagen you want to put a border around a rectangular room. summerize the steps you would use to find the length of the boarder n
Katena32 [7]
You would need to find the length of one wall then multiply it by 2 (since there are 2 walls) and then find the width and also multiply that by 2 and you would then add your to products (answers) to get the total length of your border
4 0
3 years ago
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