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vodomira [7]
3 years ago
9

Ellen casts a 5.5 foot shadow. If Ellen is 4 feet 6 inches tall, and her brother is 6 foot tall, how long of a shadow does he ca

st at the same time of day?
A) 6 ft. 8 in.

B) 7 ft. 2 in.

C) 7 ft. 4 in.

D) 7 ft. 8 in.
Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

C) 7 ft 4 in

Step-by-step explanation:

Shadows are assumed to be proportional to the height of the object casting them. Hence the brother's shadow will satisfy ...

shadow/(6 ft) = (5.5 ft)/(4.5 ft) = 11/9 . . . . . reduce the fraction

shadow = (6 ft) · (11/9) . . . . . . . . . . . . . . . . . multiply by 6 ft

shadow = 7 1/3 ft = 7 ft 4 in

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In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=4 and BC=3, Find AH, CH and BH.
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Answer:

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Step-by-step explanation:  

It can be convenient to compute the length of the hypotenuse of this triangle (AC). The Pythagorean theorem tells you ...

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And the scale factor to ∆BHC is ...  

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And the side CH is 0.6·BC = 0.6·3 = 1.8  

These two side lengths should add to the length AC = 5, and they do.  

The remaining side BH can be found from either scale factor:    

  BH = AB·0.6 = BC·0.8 = 4·0.6 = 3·0.8 = 2.4

_____  

The sides of interest are ...  

  AH = 3.2

  CH = 1.8

  BH = 2.4

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