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3 years ago

Nic wants to divide his 1/4 lb of cheese between 8 friends. How much cheese does each friend get?

Mathematics

2 answers:

Nady [450]3 years ago

6 0

the answer is a. 1/32 pounds

Snowcat [4.5K]3 years ago

4 0

Answer:

1/32 of a pound (A)

Step-by-step explanation:

Hope this helps!!!

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PLEASE HELP, WILL MARK BRAINLIEST

m_a_m_a [10]

Answer:

answer is no solution (filler)

8 0

3 years ago

19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

ElenaW [278]

Answer:

29.4 meters

Step-by-step explanation:

Given the following :

A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

distance it moved between two positions. Use the "distance on the number line "formula

Initial Position or distance of submarine before ascension = 56.8 meters

Final position after ascension = 27.4 meters

The distance moved by the submarine between the two positions can be obtained by.

(Initial distance - Final distance)

(56.8 - 27.4) = 29.4 meters

5 0

4 years ago

Question: "If y > 3, what is the value of n ?"

iris [78.8K]

Answer:

y-3

Problem:

What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?

Step-by-step explanation:

Dividend=quotient×divisor+remainder

So we have

xy-3=(x-1)×(y)+remainder

xy-3=(xy-y)+remainder *distributive property

Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.

We need to get rid of minus y so we need plus y in the remainder.

We also need minus 3 in the remainder.

So the remainder is y-3.

Let's try it out:

xy-3=(xy-y)+remainder

xy-3=(xy-y)+(y-3)

xy-3=xy-3 is what we wanted so we are done here.

7 0

3 years ago

The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

sammy [17]

Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

8 0

3 years ago

FREE PONITS<br><br><br><br> oof its really late for me lol

irinina [24]

Kkskskskdjdjdjdksksjjsdj thx

7 0

3 years ago

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