Answer:
See explanation above
Step-by-step explanation:
This problem is very similar to one I solved a few moments ago. First we need to know how much it rain during the month of august the first 15 days of august. We only know how much it rain from the 15th through the end of the month.
So if you want to know the total rainfall of the month, you only need to sum the amount of the rainfall from the first 15 days of august and the last days of the month.
To help you out, I will use the same data of the other problem, which was 8.33 cm for the first 15 days, and 4.65 for the last 15 days of august.
If you sum 8.33 and 4.65:
8.33 + 4.65 = 12.98 cm
This would be (theorically speaking) the total rainfall during this month. Now, if it's the same exercise that you have, then good, use this answer, but if it's not then, all you need to do is put the value for the first 15 days and do the sum with 4.65 cm to get the total.
Answer:
Step-by-step explanation:
400=15x+95
305=15x
20 1/3=x
The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5
we have
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2
using the graph
for x=5 the approximate value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15
the answer is
the approximate value of y is 1.15
9514 1404 393
Answer:
58.5 ft by 39 ft
Step-by-step explanation:
Let x represent the length of the two horizontal segments. Then the three vertical segments will be ...
(234 -2x)/3
The total enclosed area is the product of these dimensions:
A = (x)(234 -2x)/3
A = (2/3)(x)(117 -x)
This is the equation of a downward-opening parabola with zeros at x=0 and x=117. The maximum of the parabola will be on the line of symmetry, halfway between these zeros. The value of x there is ...
x = (0 +117)/2 = 58.5
The lengths of the vertical segments are ...
(2/3)(117 -58.5) = 2/3(58.5) = 39
The dimensions of the region enclosing the maximum area are 58.5 ft by 39 ft. The additional vertical segment is 39 ft.
_____
<em>Comment on maximum area problems</em>
You may have noticed that the total length of the fence allocated to the long sides (2×58.5 = 117) is half the total length of fence and is equal to the total length of fence allocated to the short sides (3×39 = 117).
This relationship is true in all rectangular fencing problems where the area is being maximized for a given total fence length. It doesn't matter how many partitions there are in either direction: <em>the total of horizontal lengths is equal to the total of vertical lengths</em>.
