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ivann1987 [24]
4 years ago
8

PLS HELP HERE IT IS MY LAST 5 QUESTIONS

Mathematics
2 answers:
marysya [2.9K]4 years ago
8 0

The correct answers are:

1. A.) 1/8s=80

2. B.) -5/4

3. r = -3

4. C.) 17/7

5. v = -13

Hope This Helps!!!

Can I Get Brainliest?

emmasim [6.3K]4 years ago
4 0

Give brainliest to her plzzzz

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Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x​
Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

<em>r</em> ² - 3<em>r</em> + 2 = (<em>r</em> - 2) (<em>r</em> - 1) = 0

with roots <em>r</em> = 2 and <em>r</em> = 1, so the characteristic solution is

<em>y</em> (char.) = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>)

For the <em>ansatz</em> particular solution, we might first try

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> + <em>d</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

where <em>ax</em> + <em>b</em> corresponds to the 2<em>x</em> term on the right side, (<em>cx</em> + <em>d</em>) exp(<em>x</em>) corresponds to (1 + 2<em>x</em>) exp(<em>x</em>), and <em>e</em> exp(3<em>x</em>) corresponds to 4 exp(3<em>x</em>).

However, exp(<em>x</em>) is already accounted for in the characteristic solution, we multiply the second group by <em>x</em> :

<em>y</em> (part.) = (<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)

Now take the derivatives of <em>y</em> (part.), substitute them into the DE, and solve for the coefficients.

<em>y'</em> (part.) = <em>a</em> + (2<em>cx</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

… = <em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)

<em>y''</em> (part.) = (2<em>cx</em> + 2<em>c</em> + <em>d</em>) exp(<em>x</em>) + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… = (<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

Substituting every relevant expression and simplifying reduces the equation to

(<em>cx</em> ² + (4<em>c</em> + <em>d</em>)<em>x</em> + 2<em>c</em> + 2<em>d</em>) exp(<em>x</em>) + 9<em>e</em> exp(3<em>x</em>)

… - 3 [<em>a</em> + (<em>cx</em> ² + (2<em>c</em> + <em>d</em>)<em>x</em> + <em>d</em>) exp(<em>x</em>) + 3<em>e</em> exp(3<em>x</em>)]

… +2 [(<em>ax</em> + <em>b</em>) + (<em>cx</em> ² + <em>dx</em>) exp(<em>x</em>) + <em>e</em> exp(3<em>x</em>)]

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

… … …

2<em>ax</em> - 3<em>a</em> + 2<em>b</em> + (-2<em>cx</em> + 2<em>c</em> - <em>d</em>) exp(<em>x</em>) + 2<em>e</em> exp(3<em>x</em>)

= 2<em>x</em> + (1 + 2<em>x</em>) exp(<em>x</em>) + 4 exp(3<em>x</em>)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

<em>x</em> : 2<em>a</em> = 2

1 : -3<em>a</em> + 2<em>b</em> = 0

exp(<em>x</em>) : 2<em>c</em> - <em>d</em> = 1

<em>x</em> exp(<em>x</em>) : -2<em>c</em> = 2

exp(3<em>x</em>) : 2<em>e</em> = 4

Solving the system gives

<em>a</em> = 1, <em>b</em> = 3/2, <em>c</em> = -1, <em>d</em> = -3, <em>e</em> = 2

Then the general solution to the DE is

<em>y(x)</em> = <em>C₁</em> exp(2<em>x</em>) + <em>C₂</em> exp(<em>x</em>) + <em>x</em> + 3/2 - (<em>x</em> ² + 3<em>x</em>) exp(<em>x</em>) + 2 exp(3<em>x</em>)

4 0
3 years ago
If a 3,500 investment earns 120 over 3 years, what is the annual rate?
Katarina [22]

Answer:

The annual rate of interest is 2 %

Step-by-step explanation:

Given as :

The investment amount = $ 3,500

The Interest earn on investment = $ 210

The time period = 3  years

Let The annual interest rate = R

From simple interest method :

Simple Interest =  

Or, 210 × 100 = 3500 × R × 3

Or, R =  

Or, R =  

HOPE THIS HELPED!!

5 0
3 years ago
Can someone please help me
mrs_skeptik [129]

Step-by-step explanation:

5x=4x+12(corresponding angle)

5x-4x=12

x=12

if it is correct answer then please follow me

6 0
3 years ago
How to do the problem
MrMuchimi
Order of operations are:
<span>1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
<span>4. Addition and Subtraction (from left to right)

So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)

There are no exponents so multiplication and division:
56-16/2
56-8

Finally, addition and subtraction:
56-8=48

Your second problem is a bit more complicated but follows the same rules:
</span></span>( 8^{2}+(13-4) ^{2} )/5
<span><span>
Parentheses first:
</span></span>( 8^{2}+ 9^{2})/5)
<span><span>
Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5

Now back to parentheses:
(145)/5

Division:
145/5=29

Hope that helps</span></span>
8 0
4 years ago
Solve the equation on the interval [0, 2π). <br> 3(sec x)^2 -4=0
Flauer [41]

\:  \:  \:  \:  \:

x =  \frac{\pi}{6} , \frac{(k)\pi}{6} , \frac{(5)\pi}{6} , \frac{(k)\pi}{6}

<h3><em>refer</em><em> to</em><em> the</em><em> attachment</em></h3><h2><u>hope</u><u> it</u><u> helps</u></h2><h2 />

7 0
3 years ago
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