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2 years ago

Can you just help me with 1 of the figures in my math problem and explain how you got it please!!

Mathematics

1 answer:

Phoenix [80]2 years ago

7 0

Answer:

area of triangle: 1.2975

area of circle: π ≈ 3.1416

Step-by-step explanation:

The side length (B) is used to compute the perimeter of the triangle. For the 3-sided triangle, the perimeter is ...

P = 3B = 3·1.73 = 5.19

The "height" (H) measured from the center of the circle to the middle of one side is called the "apothem" (a). The area of the triangle (A) is the product of half that and the perimeter:

A = (1/2)aP = (1/2)·0.5·5.19 = 1.2975 . . . . . . square units

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FromTheMoon [43]

Answer:

$\huge y = \sin(q) = \sin(90°) = 1$

<h2>d. 1 is the right answer.</h2>

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2 years ago

Figure BCDE was transformed using the composition rx-axis ◦ T2,2. If point B on the pre-image lies at (3, 4), what are the coord

____ [38]

Answer:

The answer is "(5, -6)"

Step-by-step explanation:

Given:

The Pre-image line at point B is: (3, 4)

Solution:

$\ rx-axis \circ \ T2,2 (3,4) \\\\\Rightarrow \ rx-axis \ ( T2,2 (3,4) )\\\\ \Rightarrow \ rx-axis ( 5,6 ) \\\\ \Rightarrow (5, -6)\\$

The coordinates of B point is (5,-6).

5 0

3 years ago

Read 2 more answers

Use slopes and y-intercepts to determine if the lines 10x+3y=−3 and 5x−4y=−3 are parallel.

kvasek [131]

Answer:

They are not parallel

Step-by-step explanation:

original equation

10x + 3y = -3

subtract 10x

3y = -10x - 3

divide by 3

y = -10/3x - 1

original equation

5x - 4y = -3

subtract 5x

-4y = -5x-3

divide by -4

y = 5/4x + 3/4

the slopes are not equal to each other (5/4x and -10/3x) so they are not parallel

4 0

1 year ago

Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of t

Illusion [34]

I hope the choices for the numerators of the solutions are given.

I am showing the complete work to find the solutions of this equation , it will help you to find an answer of your question based on this solution.

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = 10, b = -19 and c = 6.

Next step is to plug in these values in the above formula. Therefore,

$x=\frac{(-19)-\pm\sqrt{(-19)^2-4*10*6}}{2*10}$

$=\frac{19\pm\sqrt{361-240}}{20}$

$=\frac{19\pm\sqrt{121}}{20}$

$=\frac{19\pm11}{20}$

So, $x=\frac{19-11}{20} ,\frac{19+11}{20}$

$x=\frac{8}{20} , \frac{30}{20}$

So, $x= \frac{2}{5} ,\frac{3}{2}$

Hope this helps you!

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3 years ago

Read 2 more answers

Solve the following inequality: 10t + 7 , 200 > 21 , 000

Alla [95]

Answer:

t > 1380

Step-by-step explanation:

Subtract 7200 from both sides

10t + 7200 - 7200 > 21000 - 7200

Simplify

10t > 13800

Divide both sides by 10

10t/10 > 13800/10

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3 years ago