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Alexeev081 [22]
3 years ago
9

What may happen if a large number of computer users are attempting to access a web site at the same time that you are

Computers and Technology
2 answers:
Nitella [24]3 years ago
6 0
It will most likely begin to crash and eventually just freeze , i'm guessing  
Scilla [17]3 years ago
4 0
The website can freeze and crash.  An example is when Kylie Jenner restocked her lip kits so many people were on the website it crashed.
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A peripheral can be used to tell a computer to complete a specific task. True False
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I looked up the answer; I believe the answer is true.
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2 years ago
If the three operations were combined, O(logN) + O(N) * O(logN) + 1, the overall algorithm cost would be:________
KiRa [710]

Answer:

D. O(NlogN)

Explanation:

The computation of the overall algorithm cost is as follows:

Given that

O(logN) + O(N) × O(logN) + 1

In the case of complexity we considered the high order that dominates the other terms

Thus, that term would be  

O(N) × O(logN)

It could be rewrite as

O(NlogN)

Hence, the correct option is D.

All the other options are wrong

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IT professionals have a responsibility to educate employees about the risks of hot spots. Which of the following are risks assoc
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third partying and computer hackers.

Explanation:

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How can u refer to additional information while giving a presentation
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A detective agency is looking to bust an arms sale. According to available intelligence, the sale is likely to happen in one of
Paha777 [63]

Answer:

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

H(X)=5.4224 bits per symb

H(X|Y="not C")=0.54902 bits per symb

Explanation:

P(B)=2P(C)

P(A)=2P(B)

But

P(A)+P(B)+P(C)=1

4P(C)+2P(C)+P(C)=1

P(C)=1/7

Then

P(A)=4/7

P(B)=2/7

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

iii

If X={A,B,C}

and P(Xi)={4/7,2/7,1/7}

where  Id =logarithm to base  2

Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}

=-{(1/7)Id1/7 +(2/7)Id(2/7) +(4/7)Id(4/7)}

=5.4224 bits  per symb

if P(C)  =0

P(A)=2P(B)

P(B)=1/3

P(A)=2/3

H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)

=0.54902 bits per symb

4 0
2 years ago
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