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4 years ago

Where is the typical location of a touchpad inside of a laptop?

Computers and Technology

1 answer:

Yuliya22 [10]4 years ago

6 0

Attached to the keyboard is the typical location of a touchpad inside of a laptop.

Attached to the keyboard

Explanation:

The touchpad, by a long shot the most well-known sort, is a level territory, situated underneath your console. A pointing stick is a little catch situated among your PC's keys. The conventional touchpad is a rectangular, contact delicate cushion, generally focused beneath the console in the scratch pad's palm rest. Moving your finger over the outside of this cushion moves the mouse.

And the cushion is devoted left-and right-click catches, and now and again a middle snap. In the event that you need to right-tap on a workstation without utilizing the trackpad, you can do it utilizing a console easy route. Position the cursor and hold down "Move" and press "F10" to right-click. A few workstations additionally have a particular key called a "Menu" key that can be utilized for right-clicking.

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A great way to avoid tech distraction is to __

Ksivusya [100]

Answer:

Explanation:

This is because you are only restraining yourself from using your phone when you are NOT at the stop lights (or you could perhaps say Red Lights). I hope this was helpful! :)

4 0

3 years ago

Read 2 more answers

The indent buttons on the home tab allow you to increase or decrease paragraph indenting in increments of ____ inches.

TEA [102]

0.5 inches.
You may also manually set the indentation. In order to do this, click the "Page Layout" tab and enter the desired values in the boxes under "Indent". The indentation of a text is the distance it has from the left margin (when writing from left to right).

3 0

3 years ago

A person gets 13 cards of a deck. Let us call for simplicity the types of cards by 1,2,3,4. In How many ways can we choose 13 ca

natima [27]

Answer:

There are 5,598,527,220 ways to choose 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 from a set of 13 cards.

Explanation:

The crucial point of this problem is to understand the possible ways of choosing any type of card from the 13-card deck.

This is a problem of combination since the order of choosing them does not matter here, that is, the important fact is the number of cards of type 1, 2, 3 or 4 we can get, no matter the order that they appear after choosing them.

So, the question for each type of card that we need to answer here is, how many ways are there of choosing 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 are of type 4 from the deck of 13 cards?

The mathematical formula for combinations is $\\ \frac{n!}{(n-k)!k!}$ , where n is the total of elements available and k is the size of a selection of k elements from which we can choose from the total n.

Then,

Choosing 5 cards of type 1 from a 13-card deck:

$\frac{n!}{(n-k)!k!} = \frac{13!}{(13-5)!5!} = \frac{13*12*11*10*9*8!}{8!*5!} = \frac{13*12*11*10*9}{5*4*3*2*1} = 1,287$ , since $\\ \frac{8!}{8!} = 1$ .

Choosing 4 cards of type 2 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-4)!4!} = \frac{13*12*11*10*9!}{9!4!} = \frac{13*12*11*10}{4!}= 715$ , since $\\ \frac{9!}{9!} = 1$ .

Choosing 2 cards of type 3 from a 13-card deck:

$\\ \frac{n!}{(n-k)!k!} =\frac{13!}{(13-2)!2!} = \frac{13*12*11!}{11!2!} = \frac{13*12}{2!} = 78$ , since $\\ \frac{11!}{11!}=1$ .

Choosing 2 cards of type 4 from a 13-card deck:

It is the same answer of the previous result, since

$\\ \frac{n!}{(n-k)!k!} = \frac{13!}{(13-2)!2!} = 78$ .

We still need to make use of the Multiplication Principle to get the final result, that is, the ways of having 5 cards of type 1, 4 cards of type 2, 2 cards of type 3 and 2 cards of type 4 is the multiplication of each case already obtained.

So, the answer about how many ways can we choose 13 cards so that there are 5 of type 1, there are 4 of type 2, there are 2 of type 3 and there are 2 of type 4 is:

1287 * 715 * 78 * 78 = 5,598,527,220 ways of doing that (or almost 6 thousand million ways).

In other words, there are 1287 ways of choosing 5 cards of type 1 from a set of 13 cards, 715 ways of choosing 4 cards of type 2 from a set of 13 cards and 78 ways of choosing 2 cards of type 3 and 2 cards of type 4, respectively, but having all these events at once is the multiplication of all them.

5 0

4 years ago

How does technology improve productivity at home? (Select all that apply.)

Aliun [14]

Answer:

B, C

Explanation:

5 0

3 years ago

Which of these functions may be used with positional arguments? Select four options.

jeyben [28]

Answer:

AVERAGE

COUNT

SUM

MAX

Explanation:

The functions that may be used with positional arguments include:

AVERAGE

COUNT

SUM

MAX

The basic functions formulae include SUM, AVERAGE, COUNT, MAX and MIN.

SUM: This is the sum total of all the numbers in the rows.

COUNT: This is the used to count the range of cells that contains numbers.

AVERAGE: This is the average of all the numbers in the rows.

MIN: This is the lowest number in the rows.

MAX: This will return the highest number that is found in the set of values.

It should be noted that the COUNTIF is not used with positional arguments.

8 0

3 years ago