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Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...
Multiply sides by -2 :
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Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...
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Step (3)
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
<h2>A. -2</h2>
Step-by-step explanation:
![\det\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =ad-bc\\\\\det\left[\begin{array}{ccc}3&-5\\1&1\end{array}\right] =(3)(1)+(-5)(1)=3-5=-2](https://tex.z-dn.net/?f=%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3Dad-bc%5C%5C%5C%5C%5Cdet%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-5%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%20%3D%283%29%281%29%2B%28-5%29%281%29%3D3-5%3D-2)
Answer:
6 gallons
Step-by-step explanation:
You can find this using the ration method.
If, 8 gallons : 192 miles
x gallons : 144 miles
We must find the value of x, which is the number of gallons used to travel 144 miles.
Cross multiply the ratios.
192 x = 8 × 144
192 x = 1152
x = 1152 ÷ 192
x = 6
∴ It takes 6 gallons to travel 144 miles.
Answer:
A) The best way to picture this problem is with a probability tree, with two steps.
The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.
The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.
If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.
If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.
B) So a person can have a red marble and a blue marble in two ways:
1) Picking the red first and the blue last
2) Picking the blue first and the red last
C) P(R&B) = 3/5 = 60%
Step-by-step explanation:
C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5
