Please helpp ASAP<br><br> 100 points extra and brainleist

Determine whether the equation is exponential growth or exponential decay

Harman [31]

9514 1404 393

Answer:

decay
decay
growth

Step-by-step explanation:

If the base of a positive exponential is greater than 1, the function is a growth function. If it is less than 1, the function decays.

Remember that a^-1 = 1/a, so a negative exponential can be transformed to a positive one.

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1. y = 2(11/5)^-x = 2(5/11)^x . . . . 5/11 < 1, so decay

2. y = e^(-2x) = (1/e^2)^x . . . . 1/e^2 < 1, so decay

3. y = 1/4e^x . . . . e > 1, so growth

_____

e ≈ 2.71828 . . . an irrational number

4 0

3 years ago

This holiday weekend, Sue is going to Chicago to shop and to see a baseball game. To avoid traffic, Sue decides to take the trai

Pavel [41]

A proportional relationship is used to illustrate linear equations.

The constant of proportionality is 3

From the table, we have the following points:

(x,y) = (2,6) (3,9)

The constant of proportionality is calculated using:

$\mathbf{m = \frac{y_2 - y_1}{x_2 - x_1}}$

So, we have:

$\mathbf{m = \frac{9-6}{3-2}}$

Subtract

$\mathbf{m = \frac{3}{1}}$

Divide

$\mathbf{m = 3}$

Hence, the constant of proportionality is 3

Read more about constants of proportionality at:

brainly.com/question/18707816

6 0

3 years ago

The diameters of bearings used in an aircraft landing gear assembly have a standard deviation of ???? = 0.0020 cm. A random samp

vovikov84 [41]

Answer:

(a) We conclude after testing that mean diameter is 8.2500 cm.

(b) P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

(c) 95% confidence interval on the mean diameter = [8.2525 , 8.2545]

Step-by-step explanation:

We are given with the population standard deviation, $\sigma$ = 0.0020 cm

Sample Mean, Xbar = 8.2535 cm and Sample size, n = 15

(a) Let Null Hypothesis, $H_0$ : Mean Diameter, $\mu$ = 8.2500 cm

Alternate Hypothesis, $H_1$ : Mean Diameter, $\mu$ $\neq$ 8.2500 cm{Given two sided}

So, Test Statistics for testing this hypothesis is given by;

$\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ follows Standard Normal distribution

After putting each value, Test Statistics = $\frac{8.2535-8.2500}{\frac{0.0020}{\sqrt{15} } }$ = 6.778

Now we are given with the level of significance of 5% and at this level of significance our z score has a value of 1.96 as it is two sided alternative.

<em>Since our test statistics does not lie in the rejection region{value smaller than 1.96} as 6.778>1.96 so we have sufficient evidence to accept null hypothesis and conclude that the mean diameter is 8.2500 cm.</em>

(b) P-value is the exact % where test statistics lie.

For calculating P-value , our test statistics has a value of 6.778

So, P(Z > 6.778) = Since in the Z table the highest value for test statistics is given as 4.4172 and our test statistics has value higher than this so we conclude that P - value is smaller than 2 x 0.0005% { Here 2 is multiplied with the % value of 4.4172 because of two sided alternative hypothesis}

Hence P-value of test = 2 x 0.0005% = 1 x $10^{-5}$ .

(c) For constructing Two-sided confidence interval we know that:

Probability(-1.96 < N(0,1) < 1.96) = 0.95 { This indicates that at 5% level of significance our Z score will lie between area of -1.96 to 1.96.

P(-1.96 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96\frac{\sigma}{\sqrt{n} }$ < $Xbar - \mu$ < $1.96\frac{\sigma}{\sqrt{n} }$ ) = 0.95