How do you do a box and whisker plot using 18,18,17,19,20,22,22,22,22,23,25 and26
sashaice [31]
What a whisker plot exactly
Answer:
it is 10 times greater
Step-by-step explanation:
hope this helps :)
1 + tan ² Ф=sec²Ф
1+(12/5)²=sec²Ф
169/25=sec² Ф
sec Ф=⁺₋√(169/25)=⁺₋13/5
sec Ф=1/cos Ф ⇒cosФ=1/sec Ф
cos Ф>0 ⇔ sec Ф>0 ⇔ sec Ф=+ 13/5
cos Ф=1/secФ
cos Ф=1 / 13/5=5/13
we can calculate the sin Ф, with this method.
sin²Ф + cos²Ф=1 ⇒ sin Ф=⁺₋√(1-cos² Ф)
sin Ф=⁺₋√[1-(5/13)²]=⁺₋12/13
like cos Ф>0 and tan Ф>0 ⇒ sin Ф>0 ⇒sin Ф=12/13
answer: d.12/13
other method
tan Ф=sin Ф / cos Ф
12/5=sin Ф / 5/13
sin Ф=(12/5)*(5/13)=12/13
answer: d.12/13
um oki ...... -_- ahhhahahhahahah
Answer:
Step-by-step explanation:
3 pieces such that each piece is 2 cm longer then the next...
x , x + 2, x + 4
x + x + 2 + x + 4 = 30
3x + 6 = 30
3x = 30 - 6
3x = 24
x = 24/3
x = 8
x + 2 = 8 + 2 = 10
x + 4 = 8 + 4 = 12
check...
8 + 10 + 12 = 30
18 + 12 = 30
30 = 30 (correct)...it checks out
the ribbon lengths are : 8 cm, 10 cm, and 12 cm
