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Anna11 [10]
3 years ago
14

How to solve y-b/x=m for y

Mathematics
2 answers:
Slav-nsk [51]3 years ago
8 0
To solve for m we want to get m by itself on one side of the equals sign, with everything else on the other side. First we subtract b from both sides, to get it out of the right side of the equation:
y - b = mx + b - b
y - b = mx
Now we divide both sides by x, to get m completely by itself:
(y-b)/x = (mx)/x
(y-b)/x = m
So m is equal to (y-b)/x.
Marrrta [24]3 years ago
8 0

Answer:

Step-by-step explanation:

y - b/x = m

Adding b/x both sides

y = m+b/x

But i think your question you're trying to ask is (y - b)/x = m

So, for this one,

Multiply both sides by x

y-b = mx

Adding b both sides

To get: y=mx+b

Hope this helps!

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In a normally distributed data set a mean of 55 where 99.7% of the data fall between 47.5 and 62.5, what would be the standard d
NeX [460]

Given that normally distributed data set has a mean of 55 and 99.7% of data fall between 47.5 and 62.5.

Let s be the standard deviation of data set.

Since 99.7% data fall within 3 standard deviations of mean, z-value for 47.5 and 62.5 has an absolute value of 3.

That is |z|=3

But z= \frac{x-mean}{standard deviation}

Let us plugin x=47.5 and mean =55 and equate it to 3.

That is |\frac{47.5-55}{s}|  = 3

             |\frac{-7.5}{s} | =3

Since x is always positive ( being standard deviation), |\frac{-7.5}{s} | = \frac{|-7.5|}{s} = \frac{7.5}{s}

Hence  \frac{7.5}{s}= 3

             s=\frac{7.5}{3}  = 2.5

We will get same value with 62.5 as well.

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4 years ago
Can someone help me? I’ve been stuck for about an hour and my head is about to combust. Thanks!
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2.1

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Read 2 more answers
A tank is in the shape of an inverted circular cone with height 500 ft and base radius 20 ft. It is filled with water to a heigh
SashulF [63]

Answer:

1.338 * 10 ^ 9 lb-ft

Step-by-step explanation:

We have the following information:

Water density 62.4 lb / ft ^ 3

work equals force per distance, like this:

W = F * d

with the information in the statement we can deduce:

20/500 = r / y

r = y / 25

 now the differential volume would be:

dv = pi * (r ^ 2) * dy

dv = pi * ((y / 25) ^ 2) * dy

dv = pi * (y ^ 2/625) * dy

weight of slice would be:

62.4 * pi * (y ^ 2/625) * dy

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work for the removal of slice:

(500 - y) * 0.3136 * y ^ 2 * dy

Now the total work is the integral of the previous expression that goes from y = 0 to y = 400

Total work = integral (from 0 to 400) {(500 - y) * 0.3136 * y ^ 2 * dy}

Total work = integral (from 0 to 400) {0.3136 * (500 * y ^ 2 - y ^ 3) dy}

We integrate and we have:

Total work = 0.3136 * ((500/3) * y ^ 3 - (y / 4) ^ 4)

Total work = 0.3136 * ((500/3) * 400 ^ 3 - (400/4) ^ 4) - 0.3136 * ((500/3) * 0 ^ 3 - (0/4) ^ 4)

Total work = 0.3136 * ((500/3) * 400 ^ 3 - (400 ^ 4) / 4)

Total work = 1.338 * 10 ^ 9 lb-ft

5 0
3 years ago
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