Not 1 or 3
it can't be 4 so it is the second one
7y^2 + 10y + 3
7y^2 + 7y + 3y + 3
(7y^2+7y) + (3y+3)
7y(y+1) + 3(y+1)
(7y+3)(y+1)
So the final answer is <span>(7y+3)(y+1)</span>
Answer:
y=x+1
or x=y-1
Step-by-step explanation:
Answer:

And we want to evaluate e^0 using the graph
And as we can see in the plot the y intercept is the blue point with y=0 and that correspond with:

Step-by-step explanation:
For this problem we know the following function:

And we want to evaluate e^0 using the graph
And as we can see in the plot the y intercept is the blue point with y=0 and that correspond with:
