Answer:
Yes
Step-by-step explanation:
Since the circle is split into 6 pieces, we can split the probability of landing on each section into fractions
There is one piece with the number 1 on it, so there is a 1/6 chance of landing on that.
There are 3 pieces with the number 2 on it, so there is a 3/6 chance of landing on it, simplifies that would be 1/2
There is one piece with the number 3 on it, so there is a 1/6 chance of landing on that.
There is one piece with the number 4 on it, so there is a 1/6 chance of landing on that.
Since the pieces with a 1 and 4 on the both have a 1/6 probabilit of landing, there is an equal chance on landing on either tile.
It would be: 44/6 = 22/3
In short, Your Answer would be 22 : 3
Hope this helps!
Answer:
So, the required width of rectangular piece of aluminium is 8 inches
Step-by-step explanation:
We are given:
Perimeter of rectangular piece of aluminium = 62 inches
Let width of rectangular piece of aluminium = w
and length of rectangular piece of aluminium = w+15
We need to find width i.e value of x
The formula for finding perimeter of rectangle is: 
Now, Putting values in formula for finding Width w:
After solving we get the width of rectangular piece :w = 8
So, the required width of rectangular piece of aluminium is 8 inches
Answer:
28.9
Step-by-step explanation:
cosG=
hypotenuse
adjacent
=
31
x
\cos 21=\frac{x}{31}
cos21=
31
x
31\cos 21=x
31cos21=x
x=28.941\approx \mathbf{28.9}\text{ feet}
x=28.941≈28.9 feet
