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lawyer [7]
3 years ago
12

Write an equation for the line that is parallel to the given line and that passes through the given point. y = 2x + 7; (3, 11)

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0
Two lines that are parallel have the same slope.  Thus, the slope of the given line is 2 and the slope of the new line is also 2.

General slope-intercept equation of a str. line is y = mx + b.

Let m = 2:  y = 2x + b
This new line passes thru (3,11).  Thus, subst. 3 for x and 11 for y in
y = 2x + b, to find b:

11 = 2(3)+b
11 = 6 + b               so b=5

Thus, the equation of the new line, parallel to the old, is y = 2x + 5.
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A particle moves along the x-axis so that at time t ≥ 0 its position is given by x(t) = 2t3 - 21t2 + 72t - 53. At what time t is
Zepler [3.9K]

Step-by-step explanation:

The particle is at rest when the derivative of x(t), which is its velocity, is zero, i.e.,

\dfrac{d}{dt}[x(t)] = \dot{x}(t) = 0

Since x(t) = 2t^3 - 21t^2 + 72t - 53, its derivative is

\dot{x}(t) = 6t^2 - 42t + 72

Equating this to zero, we get

6t^2 - 42t + 72 = 0 \Rightarrow t^2 - 7t + 12 = 0

This is a familiar quadratic equation whose roots are

t = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

\;\;\;= \dfrac{7 \pm \sqrt{(7)^2 - 4(1)(12)}}{2}

\;\;\;= \dfrac{7 \pm 1}{2}

\;\;\;= 3\;\text{and}\;4

This means that the particle will be at rest at t = 3 and t= 4.

8 0
3 years ago
Solve the equation a-32=47 ? GIVING 30 BRAINLY'S!!
juin [17]

Answer:

a=79

Step-by-step explanation:

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3 0
3 years ago
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sesenic [268]

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4 0
3 years ago
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How do you do solve this problem
Damm [24]

Answer:

<h2>186 : 1</h2>

Step-by-step explanation:

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Therefore 8cm = 8 · 10mm = 80mm

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\dfrac{model}{real}\to\dfrac{80}{0.43}=\dfrac{80\cdot100}{0.43\cdot100}=\dfrac{8000}{43}\approx186

8 0
3 years ago
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