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Eva8 [605]
3 years ago
10

Francisco finds a Web site that defines a regular hexagon as a "six-sided polygon with six congruent angles and six congruent si

des." Is this a valid definition of a regular hexagon?
a. It is valid because regular hexagons have six sides and six angles.
b. It is not valid because some hexagons that are not regular hexagons fit the definition.
c. It is not valid because it does not say that the figure can only have six angles.
d, It is valid because all regular hexagons fit the definition, and any figure that is not a regular hexagon does not fit the defintion.
Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

d.

Step-by-step explanation:

All regular hexagons fit this definition.

Any other figure does not fit the definition.

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What is the value,in degree, of y
Viktor [21]
Y= 122.

I did the math.
6 0
3 years ago
Read 2 more answers
How to solve these two problems ?
puteri [66]

8)  \theta is -0.896 radians

9) length of arc is 41.91 cm

Solution:

8)

Given that,

tan\ \theta = \frac{-5}{4}

\theta is in quadrant 4

To find: \theta

From given,

tan\ \theta = \frac{-5}{4}\\\\\theta = tan^{-1} \frac{-5}{4}\\\\\theta = tan^{-1} (-1.25)\\\\\theta = -51.34

Thus value of \theta is -51.34 degrees

Convert degrees to radians

-51.34\ degree = -51.34 \times \frac{ \pi }{180}\ radian\\\\-51.34\ degree = -0.896\ radian

Thus \theta is -0.896 radians

9)

From given,

radius = 15.4 cm

\theta = \frac{13 \pi }{15}

<em><u>The length of arc when angle in radians is:</u></em>

arc\ length = r \times \theta\\\\arc\ length = 15.4 \times \frac{ 13 \pi }{15}\\\\arc\ length = 15.4 \times 2.721\\\\arc\ length = 41.91

Thus length of arc is 41.91 cm

4 0
3 years ago
At a fair, each person can spin two wheels of chance. The first wheel has the letters F, A, I, and R. The second wheel has the n
pickupchik [31]

Answer:

12 possible outcomes.

Sample space:

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

Step-by-step explanation:

The collection of all possible outcomes of a probability experiment forms a set that is known as the sample space.

1. There are four possible outcomes for the first wheel: F, A, I and R

2. There are three possible outcomes for the second wheel: 1, 2 and 3

So, the sample space is

\begin{array}{cccc}(F,1)&(A,1)&(I,1)&(R,1)\\(F,2)&(A,2)&(I,2)&(R,2)\\(F,3&(A,3)&(I,3)&(R,13)\end{array}

4 0
3 years ago
Yes im playing prodigy LOL
Ilya [14]

Answer:

0,05

Step-by-step explanation:

1)First, Let’s find the mean of the data table

12 + 10 + 12 + 6 + 8 + 4 + 2 + 12 = 66

66 ÷ 8 = 8,25

2)12 - 8,25 = 3,75

10 - 8,25 = 1,25

12 - 8,25 = 3,75

6 - 8,25 = -1,75

8 - 8,25 = -0,75

4 - 8,25 = -3,75

2 - 8,25 = -5,75

12 - 8,25 = 3,75

3) 3,75 + 1,25 + 3,75 - 1,75 - 0,85 - 3,75 - 5,75 + 3,75 = 0,4

0,4 ÷ 8 = 0,05

8 0
3 years ago
The ratio of dogs to cats at an animal shelter is 33 to 22. How many dogs are at the shelter if there is a total of 3030 animals
Elena-2011 [213]
D : c = 33 : 22
where d is the number of dogs and c is the number of cats;
and: d + c = 3030
33 c = 22 d  / : 11
3 c = 2 d
From the other equation: c = 3030 - d
3 * ( 3030 - d ) = 2 d
9090 - 3 d = 2 d
5 d = 9090
d = 9090 : 5
d = 1818
Answer: There are 1818 dogs in the shelter.
 
4 0
3 years ago
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