$\bf sec\left( \frac{\pi }{6} \right)\qquad recall\to sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus
\\\\
sec\left( \frac{\pi }{6}\right)\iff \cfrac{1}{cos\left( \frac{\pi }{6}\right)}
\\\\\\
\textit{check your Unit Circle for what the }cos\left( \frac{\pi }{6}\right)\ is
\\\\\\
\cfrac{1}{\frac{\sqrt{3}}{2}}\implies \cfrac{\frac{1}{1}}{\frac{\sqrt{3}}{2}}\implies 
\cfrac{1}{1}\cdot \cfrac{2}{\sqrt{3}}\implies \cfrac{2}{\sqrt{3}}$

3 0

3 years ago

A rectangle in Quaderant 1 is transformed to produce a congruent rectangle in Quaderent 2. Which could describe the transformati

Leviafan [203]

Answer:

A translation

Step-by-step explanation:

The rectangle doesn't change, it just scoots over.

6 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

mihalych1998 [28]

Answer:

∠KJL and ∠KJG

Step-by-step explanation:

8 0

3 years ago

A farmer sells 8.9 kilograms of apples and pears at the farmer's market. 3 /4 of this weight is apples, and the rest is pears. H

aleksandrvk [35]

Answer: 2.225 kg

Step-by-step explanation:

You know that:

- The total weight the farmer sold was 8.9 kilograms.

- 3/4 of this weight is apples, and the rest is pears.

Therefore, to calculate the amount of kilograms of pears she sold at the farmer's market (which you can call x), you need to apply the following proccedure.

Thefore, you obtain the following result:

$x=8.9kg-(8.9kg*\frac{3}{4})\\x=2.225kg$

4 0

3 years ago

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