The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Jim- 60× .45= 27
Dora- 10 of the 60
Ada- 60× .25= 15
Kim- 8 remaining
Jim placed the most with 27
Levant will receive about 9 american dollars when he exchanges his pesos.
According to this question, 1 american dollar is worth about 11 pesos. In order to find that, you need to divide 3000/270 which gives you around 11. In order to find out how many dollars he will receive for his pesos, you need to divide 100 by 11 which gives you about 9 dollars.
Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.
Step-by-step explanation:
1). 2x + 3y = 33
2). 5x + 2y = 55
3). I’m going to use substitution.
Isolate a variable (x):
2x + 3y = 33
2x = -3y + 33
X = (-3y + 33)/2
X = -3/2y + 33/2
Substitute and solve for y:
5x + 2y = 55
5(-3/2y + 33/2) + 2y = 55
-15/2y + 165/2 + 2y = 55
-11/2y = -55/2
Y = 5 <— children’s ticket.
Solve for x:
2x + 3y = 33
2x + 3(5) = 33
2x + 15 = 33
2x = 18
X = 9 <— adult’s ticket.
Check:
5x + 2y = 55
5(9) + 2(5) = 55
45 + 10 = 55
55 = 55
2x + 3y = 33
2(9) + 3(5) = 33
18 + 15 = 33
33 = 33
Answer:
34
Step-by-step explanation:
The mean is calculated as
mean = 
let x be the missing frequency, then
Total frequency × midpoint
= (16 × 2) + 7x + (20 × 12) + (10 × 17) = 32 + 7x + 240 + 170 = 442 + 7x
Total frequency = 16 + x + 20 + 10 = 46 + x, thus
= 8.5 ( cross- multiply )
442 + 7x = 8.5(46 + x)
442 + 7x = 391 + 8.5x ( subtract 8.5x from both sides )
442 - 1.5x = 391 ( subtract 442 from both sides )
- 1.5x = - 51 ( divide both sides by - 1.5 )
x = 34
The missing frequency is 34
