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2 years ago

Help Por favor! Will mark brainliest!

Mathematics

1 answer:

postnew [5]2 years ago

8 0

Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.

Step-by-step explanation:

1). 2x + 3y = 33

2). 5x + 2y = 55

3). I’m going to use substitution.

Isolate a variable (x):

2x + 3y = 33

2x = -3y + 33

X = (-3y + 33)/2

X = -3/2y + 33/2

Substitute and solve for y:

5x + 2y = 55

5(-3/2y + 33/2) + 2y = 55

-15/2y + 165/2 + 2y = 55

-11/2y = -55/2

Y = 5 <— children’s ticket.

Solve for x:

2x + 3y = 33

2x + 3(5) = 33

2x + 15 = 33

2x = 18

X = 9 <— adult’s ticket.

Check:

5x + 2y = 55

5(9) + 2(5) = 55

45 + 10 = 55

55 = 55

2x + 3y = 33

2(9) + 3(5) = 33

18 + 15 = 33

33 = 33

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3 years ago

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A bag contains 105 red and blue marbles. The ratio of red to blue marbles is 2:5. How many red marbles are in the bag?

V125BC [204]

Answer:

30 red marbles

Step-by-step explanation:

If the ratio is 2 red marbles for every 5 blue marbles then you would add them together to find out how many marbles are in one group.

2+5=7

There are 7 marbles in each group.

Now we have to find out how many total groups there are by dividing the total amount of marbles by the amount in each group.

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2 years ago

5. Write each number in another form.

sukhopar [10]

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3 years ago

the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.

marshall27 [118]

Answer:

$k=\frac{153}{124}$

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

$p(y)=ky^3+3y^2-3$

When p(y) is divided by y-5, the remainder is

$p(5)=k(5)^3+3(5)^2-3$

$p(5)=125k+75-3$

$p(5)=125k+72$

When the second polynomial:

$m(y)= 2y^3-5y+k$ is divided by y-5.

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$\implies 125k-k=225-72$

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2 years ago

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