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4 years ago

Carmen drew this figure to represent the dividend of a division expression.

Mathematics

2 answers:

Anon25 [30]4 years ago

8 0

Answer:

It is 9

Step-by-step explanation:

Start counting how many spaces it is from the zero to the end of the arrow which is 9.

kodGreya [7K]4 years ago

4 0

9 is the answers you’re looking for

You might be interested in

If a cross section of the paperweight is cut perpendicular to the base but does not pass through the top vertex, which shape des

Montano1993 [528]

Rectangle shape paper weight

4 0

4 years ago

Kamran wins the big game lottery. He invests part of his winnings in treasury bonds promising a 5% annual return and he deposits

Ostrovityanka [42]

Answer:

Amount won by Kamran = $21,450

Step-by-step explanation:

This can be calculated using the following 3 steps:

Step 1: Calculation of the amount invested in treasury bonds

Since the limit to the duration of investment is not stated, the amount invested can be calculated using the formula for calculating the present value of a perpetuity as follows:

PV = P / r …………………………………. (1)

Where;

PV = Present value or the amount invested treasury bonds = ?

P = Annual return on his investments = $661.25

r = Annual rate of return = 5%, or 0.05

Substitute the values into equation (1), we have:

PV = $661.25 / 0.05 = $13,225

Step 2: Calculation of the amount deposited in the money market account

From Step 1 above, we have:

Amount invested treasury bonds = $13,225

Since he invests $5000 more in treasury bonds than he deposits in the money market account, the amount deposited in the money market account can be calculated as follows:

Amount deposited in the money market account = Amount invested treasury bonds - $5,000 = $13,225 - $5,000 = $8,225

Step 3: Calculation of the amount won by Kamran

Amount won by Kamran = Amount invested treasury bonds + Amount deposited in the money market account = $13,225 + $8,225 = $21,450

7 0

3 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago

HELPPPP!!!!!!!!!!!!!

juin [17]

I think its C Because Aob is a given angle Boc is where we prove Aob so Im 95% sure its c

4 0

2 years ago

Solve for the formula for the indicated variable. Solve A=1/2bh for b.

choli [55]

B = 2A/h

The way you would get this is first by clearing the fraction. So in order to clear the fraction, you have to multiply the equation by the denominator.

2(A = 1/2bh)

2A = 1bh

2A = bh

Then you have to isolate the variable. So you'd divide bh by h in order to get b by itself. So you'd end up with:

2A/h = bh/h

2A/h = b

5 0

3 years ago