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trasher [3.6K]
3 years ago
14

6×7=(6×5)+(6×2) The number sentence is an example of which multiplication property

Mathematics
2 answers:
gogolik [260]3 years ago
3 0
Distributive property
Naily [24]3 years ago
3 0
The distributive property. 
Hope this helps!
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Using the list below, what is the ratio of goats to the total number of animals at the zoo? Animals at a Petting Zoo Chickens 2
NemiM [27]

Answer:

Ratio of goat to total number of animals at the zoo = 2 : 5

Step-by-step explanation:

Chickens = 2

Deer = 4

Donkeys = 3

Goats = 6

Total animals at the zoo = 15

what is the ratio of goats to the total number of animals at the zoo?

Ratio of goat to total number of animals at the zoo = 6 : 15

= 6/15

= 2/5

Ratio of goat to total number of animals at the zoo = 2 : 5

3 0
2 years ago
The shortest warmer was blue. The two longest warmers were pink.
bogdanovich [222]

Answer:

8

Step-by-step explanation:

The shortest leg warmer:

4.5

The longest leg warmers:

6 and 6.5

6 + 6.5 = 12.5

12.5 - 4.5 = 8

4 0
2 years ago
What is the answer? pls help
worty [1.4K]

Answer:

117

Hope this helped :)

8 0
3 years ago
-5x^2-6=-4x using the Quadratic Formula.
a_sh-v [17]

Answer:

Step-by-step explanation:

-5x² - 6 = -4x

-5x² + 4x - 6 = 0

a = -5  ; b = 4  ; c = -6

Discriminant = b² - 4ac

                     = 4² - 4*(-5)*(-6)

                     = 16 - 120

                     = -104

roots = \dfrac{-b+\sqrt{D}}{2a} \ ; \   \dfrac{-b-\sqrt{D}}{2a}

=\dfrac{-4+\sqrt{-104}}{2*(-5)};\dfrac{-4-\sqrt{-104}}{2*(-5)}\\\\=\dfrac{-4+2i\sqrt{26}}{-10} ; \dfrac{-4-2i\sqrt{26}}{-10}\\\\=\dfrac{(-2)[2-i\sqrt{26}]}{-10} \ ; \ \dfrac{(-2)[2+i\sqrt{26}]}{-10}\\\\=\dfrac{2-i\sqrt{26}}{5} \ ; \ \dfrac{2+i\sqrt{26}}{5}

5 0
3 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
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