The function represents the profit, and the company obviously wants to maximize it.
You can see that the profit increases until the parabola reaches its maximum.
The coordinate of the maximum look like (1.5, 90)
This means that, if the company invests 1.5 thousand dollars, the profit will be 90 thousand dollars, and this is the maximum profit the company can reach.
Answer:
FV= $669.11
Step-by-step explanation:
Giving the following information:
Purchase price (PV)= $800
Decrease value (d)= 1.5% per year
Number of periods (n)= 12 years
<u>To calculate the value of the card after 12 years, we need to use the following formula:</u>
FV= PV / (1 + d)^n
FV= 800 / (1.015^12)
FV= $669.11
The answer is y=24 your welcome
<span>"A TV is on sale at 30% off for $420"
What was the original price of the TV?
</span>
Well if you start to calculate first off you are sooner or later going to figure out that in order for it to be 420 the answer has to be bigger than 1,000. If you get to 1,200 and calculate 30 percent off of it it the answer is 360 so a ballpark quesstiminate would be to go two more hundredths up. Therefore 30 percent of 1,400 is 420
Answer:
The correct answer is p

Step-by-step explanation:
An inequality compares two quantities unlike an equality. An inequality is written with either a greater than ( > ) or lower than ( < ) or greater than equal to ( ) or less than equal to ( ) signs. We solve the above given inequality to find the solutions of the unknown p. An inequality reverses if and only if we we multiply both sides with a negative quantity. Addition or subtraction does not change the sign in the inequality.
