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3 years ago

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The point (2,7) is successfully reflected across the x-axis then y-axis and than the x-axis again. What is the area of the recta

ngle formed by these 4 points ?

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

You might be interested in

mojhsa [17]

Answer:

cost = 8p + 5

Step-by-step explanation:

$8*[number of pizzas] + $5 delivery fee

$8p + $5

8p + 5

cost = 8p + 5

3 0

2 years ago

Read 2 more answers

Using y=mx+b find the slope for<br> 7) 8x + 3y = −9

malfutka [58]

Answer:

-8/3

Step-by-step explanation:

8x + 3y = - 9

Let's make y the subject of the formula.

y = - 9/3 - 8x/3

Rearrange

y = - 8x/3 - 3

The slope is the coefficient of x which is - 8/3

If you don't understand, please leave a comment

Please gimme brainliest

7 0

2 years ago

15 points to whoever answers correct

Pepsi [2]

<u>Answer</u>

C. 4 + 6

D. 3.15151515.. + 4.6

E. √64 × √25

<u>Explanation</u>

A rational number is a number that can be expressed as a quotient or a fraction. That is it can be written as a/b.

π×6 = 6π ⇒ can not be written as a rational number.

√3 + √5 ⇒ the sum of two irrational numbers can not be rational.

4 + 6 = 10. Ten is a rational number. it can be written as 10/1

3.15151515.. + 4.6 = 104/33 + 23/5

= 1279/165

√64 × √25 = 8×5=40 This can be written as 40/1

5 0

3 years ago

Consider the initial value problem y′+5y=⎧⎩⎨⎪⎪0110 if 0≤t<3 if 3≤t<5 if 5≤t<[infinity],y(0)=4. y′+5y={0 if 0≤t<311 i

rosijanka [135]

It looks like the ODE is

$y'+5y=\begin{cases}0&\text{for }0\le t$

with the initial condition of $y(0)=4$ .

Rewrite the right side in terms of the unit step function,

$u(t-c)=\begin{cases}1&\text{for }t\ge c\\0&\text{for }t$

In this case, we have

$\begin{cases}0&\text{for }0\le t$

The Laplace transform of the step function is easy to compute:

$\displaystyle\int_0^\infty u(t-c)e^{-st}\,\mathrm dt=\int_c^\infty e^{-st}\,\mathrm dt=\frac{e^{-cs}}s$

So, taking the Laplace transform of both sides of the ODE, we get

$sY(s)-y(0)+5Y(s)=\dfrac{e^{-3s}-e^{-5s}}s$

Solve for $Y(s)$ :

$(s+5)Y(s)-4=\dfrac{e^{-3s}-e^{-5s}}s\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}{s(s+5)}+\dfrac4{s+5}$

We can split the first term into partial fractions:

$\dfrac1{s(s+5)}=\dfrac as+\dfrac b{s+5}\implies1=a(s+5)+bs$

If $s=0$ , then $1=5a\implies a=\frac15$ .

If $s=-5$ , then $1=-5b\implies b=-\frac15$ .

$\implies Y(s)=\dfrac{e^{-3s}-e^{-5s}}5\left(\frac1s-\frac1{s+5}\right)+\dfrac4{s+5}$

$\implies Y(s)=\dfrac15\left(\dfrac{e^{-3s}}s-\dfrac{e^{-3s}}{s+5}-\dfrac{e^{-5s}}s+\dfrac{e^{-5s}}{s+5}\right)+\dfrac4{s+5}$

Take the inverse transform of both sides, recalling that

$Y(s)=e^{-cs}F(s)\implies y(t)=u(t-c)f(t-c)$

where $F(s)$ is the Laplace transform of the function $f(t)$ . We have

$F(s)=\dfrac1s\implies f(t)=1$

$F(s)=\dfrac1{s+5}\implies f(t)=e^{-5t}$

We then end up with

$y(t)=\dfrac{u(t-3)(1-e^{-5t})-u(t-5)(1-e^{-5t})}5+5e^{-5t}$

3 0

3 years ago

Edie is one year old,she naps from 12:45p.m to 2:30p.m how long is edies nap

4vir4ik [10]

Answer:

1:45 (one hour and 45 minutes)

Step-by-step explanation:

12:45 - 1:45 = 1 hr.

1:45 - 2:30 = 45 min.

6 0

3 years ago

Read 2 more answers