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scZoUnD [109]
3 years ago
11

For the function h(x) = x2- 2, find the range: If the domain is {-1, 0, 3}

Mathematics
1 answer:
DedPeter [7]3 years ago
8 0

Answer:

-4, -2, 4

Step-by-step explanation:

-1(2)-2

0(2)-2

3(2)-2

I hope this helped.

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Solve the inequality:<br><br> 3/10 is greater than or equal to k - 3/5
Ostrovityanka [42]

To solve the inequality 3/10 is greater than or equal to k - 3/5, we must first set it up. Since 3/10 is greater than or equal to something, we will have a greater than or equal to symbol, with the 'mouth' pointing towards 3/10. Setting this up we get:

3/10 ≥ k - 3/5

Now we want to get k by itself on one side. We can do this by adding 3/5 to each side.

3/10 + 3/5 ≥ k

Simplify

9/10 ≥ k

3 0
3 years ago
Round <br> 0.99999999<br> to four decimal places?
natali 33 [55]
1.0000!

if this is rigtht please give brainliest, if you need an explication let me know :)
7 0
3 years ago
Need ASAP! <br><br> six less than twice a number is half the number plus twelve
kolezko [41]
I’m sorry but i don’t know what ur saying
5 0
3 years ago
Simplify 9 - {x - (7 + x)}.
r-ruslan [8.4K]
Let's simplify step-by-step.

<span><span>9−x</span>−<span>(<span>7+x</span>)

</span></span>Distribute the Negative Sign:

<span>=<span><span>9−x</span>+<span><span>−1</span><span>(<span>7+x</span>)

</span></span></span></span><span>=<span><span><span><span>9+</span>−x</span>+<span><span>(<span>−1</span>)</span><span>(7)</span></span></span>+<span><span>−1</span>x

</span></span></span><span>=<span><span><span><span><span><span>9+</span>−x</span>+</span>−7</span>+</span>−x

</span></span>Combine Like Terms:

<span>=<span><span><span>9+<span>−x</span></span>+<span>−7</span></span>+<span>−x

</span></span></span><span>=<span><span>(<span><span>−x</span>+<span>−x</span></span>)</span>+<span>(<span>9+<span>−7</span></span>)

</span></span></span><span>=<span><span>−<span>2x</span></span>+2

</span></span>Answer:

<span>=<span><span>−<span>2x</span></span>+<span>2</span></span></span>
6 0
3 years ago
Read 2 more answers
In fig. AB = AC, D is the midpoint of BC.<br><br> (i)Is  ADB ADC (ii) Is ∠B =∠C?
dexar [7]

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

\triangleADB\cong\triangleADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

3 0
3 years ago
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