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3 years ago

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

$\triangle$ ADB $\cong\triangle$ ADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

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1, -c/2 < -1.5 2. -y/2 < 6 3. -d/3 > -9

irina1246 [14]

Answer:

um ight if your asking me if there are right i guess they are...

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2 years ago

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.

Elanso [62]

Answer:

2 and 5

Step-by-step explanation:

The slope-intercept form of a line is y=mx-b where m is slope and b is y-intercept.

The point-slope form of a line is y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

The standard form a line is ax+by=c.

So anyways parallel lines have the same slope.

So if we are looking for a line parallel to 3x-4y=7 then we need to know the slope of this line so we can find the slope of our parallel line.

3x-4y=7

Goal: Put into slope-intercept form

3x-4y=7

Subtract 3x on both sides:

-4y=-3x+7

Divide both sides by -4:

$y=\frac{-3}{-4}x+\frac{7}{-4}$

Simplify:

$y=\frac{3}{4}x+\frac{-7}{4}$

So the slope of this line is 3/4. So our line that is parallel to this one will have this same slope.

So we know our line should be in the form of $y=\frac{3}{4}x+b$ .

To find b we will use the point that is suppose to be on our new line here which is (x,y)=(-4,-2).

So plugging this in to solve for b now:

$-2=\frac{3}{4}(-4)+b$

$-2=-3+b$

$3-2=b$

$b=1$

so the equation of our line in slope-intercept form is $y=\frac{3}{4}x+1$

So that isn't option 1 because the slope is different. That was the only option that was in slope-intercept form.

The standard form of a line is ax+by=c and we have 2 options that look like that.

So let's rearrange the line that we just found into that form.

$y=\frac{3}{4}x+1$

Clear the fractions because we only want integer coefficients by multiplying both sides by 4.

This gives us:

$4y=3x+4$

Subtract 3x on both sides:

$-3x+4y=4$

I don't see this option either.

Multiply both sides by -1:

$3x-4y=-4$

I do see this as a option. So far the only option that works is 2.

Let's look at point slope form now.

We had the point that our line went through was (x1,y1)=(-4,-2) and the slope,m, was 3/4 (we found this earlier).

y-y1=m(x-x1)

Plug in like so:

y-(-2)=3/4(x-(-4))

y+2=3/4 (x+4)

So option 5 looks good too.

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3 years ago

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The cost table shows the average cost, a(x), of producing x number of earbuds.

Tasya [4]

Answer:

Step-by-step explanation:

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3 years ago

C/- 4 = 16 please help

Yuri [45]

Answer:

c = -64

Explanation:

c/(-4) = 16

multiply the equation by -4,

c/(-4) × (-4) = 16 × (-4)

c = 16 × (-4)

c = -64

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2 years ago

Read 2 more answers

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

Step 1: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

Step 2: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

Step 3: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

Step 4: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

Step 5: There is enough evidence to support the claim that the population mean is greater than 100.

Alternatively: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

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3 years ago