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Nezavi [6.7K]
3 years ago
11

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

\triangleADB\cong\triangleADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

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Point S is on line segment R T ‾ RT . Given R S = 4 x − 10 , RS=4x−10, S T = 2 x − 10 , ST=2x−10, and R T = 4 x − 4 , RT=4x−4, d
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Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS

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Given that

RS = 4x − 10

ST=2x−10

RT=4x−4

From the question above:

Point S lies on |RT|

So, RT = RS + ST

Substitute values for each in the above equation to solve for x

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4x - 4 = 4x + 2x - 10 - 10

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