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3 years ago

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

Mathematics

1 answer:

dexar [7]3 years ago

3 0

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

$\triangle$ ADB $\cong\triangle$ ADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

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Solve equation by completing the square round to the nearest hundredth if necessary X2-4x-=5

kipiarov [429]

Answer:

x=-1 and x=5

Step-by-step explanation:

we have

$x^{2} -4x=5$

Solve it by completing the square method

We take the coefficient of x that is -4, divide it by 2 and then square it

$-\frac{4}{2}=-2$

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