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Nezavi [6.7K]
3 years ago
11

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

\triangleADB\cong\triangleADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

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Step-by-step explanation:

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<em>Since it is an isosceles triangle, WRX = WSY</em>

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<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>

<em>--> Solve it using the cos theta rule</em>

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