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Nezavi [6.7K]
3 years ago
11

In fig. AB = AC, D is the midpoint of BC. (i)Is  ADB ADC (ii) Is ∠B =∠C?

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:

(i) Yes

(ii) Yes

Step-by-step explanation:

We are given that

AB=AC

(i)D is the mid-point of BC

BD=DC

In triangle ADB and triangle ADC

AD=AD

Reason: Reflexive property

BD=DC

Reason:Given

AB=AC

Reason: Given

\triangleADB\cong\triangleADC

Reason:SSS postulate

Yes, triangle ADB is congruent to triangle ADC

(ii) Angle B=Angle C

Reason: CPCT

Yes , angle B=angle C

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Can someone help I’m confused
PtichkaEL [24]
Since the slope is -2 we know that m=-2. Now use the standard form of y=mx+b and plug in the coordinates (-8,2). We know y=2, x=-8, and m=-2. Therefore we get 2=-2(-8)+b. Now solve for b and you get -14. Therefore, the equation is y=-2x-14.
Hope this helped!
4 0
2 years ago
Calculate the mean given the frequency table
ratelena [41]

Answer:

15.6

Step-by-step explanation:

First, multiply the midpoint of each class by its frequency, as follows:

            Class      midpoint   frequency   midpoint*frequency  

            0-9         4.5             24                4.5*24 = 108

            10-19      14.5            20                14.5*20 = 290

            20-29    24.5           32                24.5*32 = 784

Total                                      76               1182

The mean is computed as the division between the addition of the "midpoint*frequency" column by the addition of "frequency" column.

mean = 1182/76 ≈ 15.6

 

5 0
3 years ago
What is 8x -5+2 x simplified
IgorC [24]

8x -5+2 x

8x+2x-5 ( combine like terms)

answer:

10x-5 or -5+10x

8 0
3 years ago
X − 5 = 17<br> A) x = 22 <br> B) x = 12 <br> C) x = 3.4 <br> D) x = -12
Maksim231197 [3]
A is the correct answer coz if you substitute 22 in the place of X-5 the answer will be 17
8 0
3 years ago
A square rug has an inner square in the center. The side length of the inner square is x inches and the width of the outer regio
Gwar [14]

Answer: area of the outer part of the​ rug= 16 -x²

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a square: Side²

Since the area of the rug including the inner square is:  

Area of the rug = 4² =16 in²

And the area of the inner square is equal to:

Area if the inner square = x²

To obtain the area of the outer part of the rug we have to subtract the area of the inner square to the area of the rug.

Area of the outer part of the rug= 16 -x²

Feel free to ask for more if needed or if you did not understand something.

6 0
3 years ago
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