Answer:
a. 100%
b. 50%
c. 66.6%
Explanation:
a.
The memory references D6, 58, D8, 9A, DE and 5C all results in misses and the miss ratio is 100 (that is , 6 misses/ 6 references*100 = 100%)
b.
If fully associative cache is used, there will be a 3 cache misses with miss ratio of (3/6*100) = 50%.
c.
With a 2-way set-associative cache, 4 memory reference misses will occur, with a miss ratio of (4/6*100)= 66.6% misses.
Answer:
The answer is "Unstructured"
Explanation:
In comparison, unstructured information applies to information, which doesn't suit the conventional column and rows concerning databases properly. It is also known as sources, that include mails, audio and video files, web pages and posts in communication networks.
- This tracks and communicates on travel and object flow-through sensors and much more.
- These types of data are used in both companies and organizations.
Answer:
1.
DIM myArray(10) as INTEGER
LET A = 0
FOR I = 1 TO 10 STEP 2
INPUT “INPUT NUMBER”; myArray(i)
LET A = A + myArray(i)
NEXT
PRINT A
END
2.
REM PROGRAM FOR CALCULATING THE SIMPLE INTEREST
CLS
INPUT “INPUT THE PRINCIPAL”; P
INPUT “INPUT THE TIME”; T
INPUT “INPUT THE RATE”;R
SI = P* T * R / 100
PRINT “SIMPLE INTEREST =”; SI
END
Explanation:
Please find the respective programs in the answer section.
Answer:
i dont know sorry but answer above lol
Explanation:
Answer:
I'm already in high school but at first, I was scared for my life literally. It wasn't what I expected it to be, though. Everyone was super nice to me and has been ever since I started. Turns out, high school is amazing.
Explanation: