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defon
3 years ago
6

What is the average rate of change for the given function from x=-1 to x=2

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
I believe your answer would be -2.

Hope this helps,
♥<em>A.W.E.<u>S.W.A.N.</u></em>♥
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Type the correct answer in each box. Use numerals instead of words.
Alex_Xolod [135]

Answer:


Step-by-step explanation:

Given that prices for a pair of shoes lie in the interval

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Delivery fee 20% of price.  

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So domain =[80,180]

---------------------------------

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105+42 =147

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=[84, 189]

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[80,147]




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Anna007 [38]

Answer:

gr8 thx for points btw can i have brainliest

Step-by-step explanation:

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3 years ago
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Answer:

c

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c is always a good guess

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4 years ago
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Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

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3 years ago
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