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scoundrel [369]
3 years ago
8

If 7x 2a = 3x 5a, what is x equivalent to?

Mathematics
1 answer:
stepladder [879]3 years ago
6 0
X is equivalent to -4
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Estimate to find the quotient if 823 divided by 23​
ivanzaharov [21]

Answer:

Step-by-step explanation:

35.7826087

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3 years ago
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Can someone please help me with this? I'll give brainliest :)
vlabodo [156]

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

<h3>How to determine the slope?</h3>

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

m = \frac{y_2 -y_1}{x_2-x_1}

<u>16. y = 3x - 4</u>

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

m = \frac{11  - 2}{5 - 2}

m = \frac{9}{3}

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

<u>17. y = 2x^2-4x - 2</u>

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

m = \frac{28  + 2}{5 - 2}

m = \frac{30}{3}

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

Read more about slopes at:

brainly.com/question/3605446

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3 0
2 years ago
Simplify the following expression.<br> log(9x^5) + 5 log (1/x)
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Answer:

log9

Step-by-step explanation:

hello :

note :  a>0 and b>0

1) log(ab) = loga+logb

2) loga^n = nloga.....n in N

log(9x^5) + 5 log (1/x) = log(9x^5) +  log (1/x)^5 = log((9x^5) (1/x)^5)

                                 = log(9x^5)/(x^5)) = log9  because : (1/x)^5 = 1/x^5

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sladkih [1.3K]

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Equation:2x + 3

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