Question

Can someone please help me with this? I'll give brainliest :)

Answer 1

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

How to determine the slope?

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

$m = \frac{y_2 -y_1}{x_2-x_1}$

16. y = 3x - 4

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

$m = \frac{11 - 2}{5 - 2}$

$m = \frac{9}{3}$

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

17. y = 2x^2-4x - 2

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

$m = \frac{28 + 2}{5 - 2}$

$m = \frac{30}{3}$

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

Read more about slopes at:

brainly.com/question/3605446

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