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olga nikolaevna [1]
3 years ago
14

Simplify 24x5 y6 . A) 2x2 y3 6x B) 4x2 y3 6x C) 6x2 y3 4x D) 6x2 y3 2x

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer : A 2x^2y^3\sqrt{6x}

\sqrt{ 24x^5y^6}

Take square root for each term and simplify it

\sqrt{24} *\sqrt{x^5}  *\sqrt{y^6}

\sqrt{24}=\sqrt{4 * 6}  = 2\sqrt{6}

\sqrt{x^5} = x^2\sqrt{x}

\sqrt{y^6} = y^3

so we will get

2\sqrt{6} *  x^2\sqrt{x} * y^3

2x^2y^3\sqrt{6x}

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Ronald Dairo is helping the local indus-
nadya68 [22]

Answer:

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

Step-by-step explanation:

Papaya rosette pieces on first day = 5890

Papaya rosette Pieces on second day = 7020

Papaya rosette Pieces of third day = 8150

Let

a_1 = 5890\\a_2 = 7020\\a_3 = 8150

We can check if these numbers are part of a sequence.

In order to check, common difference will be found first.

d = a_2-a_1 = 7020-5890 = 1130\\d =a_3-a_2 = 8150-7020 = 1130

It can be observed that the common difference is same. When the common difference is same, the sequence is said to be an arithmetic sequence.

The formula for arithmetic sequence is given by:

a_n = a_1+(n-1)d

Putting the values

a_n = 5890+(n-1)(1130)\\a_n = 5890+1130n-1130\\a_n =4760+1130n

The formula for nth term can be used to find any term. As we have to find the number of papaya rosette pieces after two weeks which means that we need to find the number of pieces on 14th day.

So,

a_{14}= 4760+1130(14)\\a_{14} = 4760+15820\\a_{14} = 20580

Hence,

Mr. Dairo can produce 20580 pieces of Papaya rosette in two weeks.

5 0
3 years ago
Estimated m 60=4m <br><br><br><br><br> 4x0=
11111nata11111 [884]

[ Answer ]


M = <em><u>15</u></em>

4 * 0 = <u><em>0</em></u>

[ Explanation ]


60 / 4 = 15

15 * 4 = 60



4 * 0 = 0


<> Eclipsed <>


4 0
3 years ago
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Answer:

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Step-by-step explanation:

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16 = 2x²

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