Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
9) v= -12
10) n= -7
Step-by-step explanation:
9) v - 15 = -27
Add 15 from both sides
i.e. v - 15 + 15 = -27 + 15
v = -12
10) n + 16 = 9
Subtract 16 from both sides
i.e. n + 16 - 16 = 9 - 16
n = -7
Hope this helps!!!
Answer: 1/2
Step-by-step explanation: 1/3 + 1/6
1- multiply 1/3 by 2
2- 2/3 + 1/6= 3/6
3- reduce to 1/2
hope this helps pls mark me brainliest
159.98 divided by 6 is 26.66, hopefully this is correct...