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3 years ago

CHECK MY PAGE GEOMETRY PLEASE HELP FAST

Mathematics

1 answer:

Alisiya [41]3 years ago

3 0

Answer:

ok sure

Step-by-step explanation:

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Find the area of the trapezoid. Answer without units.

Leto [7]

Answer:

180

Step-by-step explanation:

Since the type of trapezoid is not listed, I cannot really explain, sorry :/

5 0

3 years ago

Use function g, shown in the graph below.

Katyanochek1 [597]

You should search it up on Photomath is easier

5 0

4 years ago

Read 2 more answers

Find the diameter of the object.

Anni [7]

Answer:

1 $\frac{1}{5}$ centimeters

Step-by-step explanation:

The diameter is equal to the radius × 2. We know that the radius is equal to 3/5 centimeters.

To solve this you must do $\frac{3}{5}$ × 2.

This equals $\frac{6}{5}$ , or 1 $\frac{1}{5}$ cm.

5 0

3 years ago

Need help with this question

goldfiish [28.3K]

Answer:

x = 12

Step-by-step explanation:

Complementary angles add up to have a sum of 90 degrees. We can create an equation and solve for x.

3x + 6x - 18 = 90

~Simplify

9x - 18 = 90

~Add 18 to both sides

9x = 108

~Divide 9 to both sides

x = 12

Best of Luck!

4 0

3 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

3 years ago