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SVEN [57.7K]
4 years ago
6

4. Find x if PQ = RS, PQ = 9x - 7, and RS = 29.

Mathematics
1 answer:
Gnoma [55]4 years ago
4 0

Answer:

x=4

Step-by-step explanation:

Because we know that PQ = RS, we can use the transitive property to replace PQ in the first equation with 29:

9x-7=29

1) Add 7 to both sides:

9x=36

2) divide by 9 on both sides:

x=4

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The property is commutative property also known as flip flop property to some people
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3 years ago
Image attached below
Alika [10]

Answer: n = 6

Step-by-step explanation:

The red dot(n) is on 6 so n =6

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3 years ago
Solve the proportional<br> equation below:<br> x/4 = x-6/3
aleksandrvk [35]
<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

                \boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}

\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}      ‏‏‎      ‏‏‎‎      \mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}‏‏‎‎

             \boxed{\mathsf{3x = 4(x - 6)}}

Apply the distributive property:

\mathsf{3x = 4(x-6)}

\mathsf{3x = 4(x) - 4(6)}

\mathsf{3x = 4x - 24}

Add 24 to both sides:

\mathsf{3x + 24 = 4x - 24 + 24}

\mathsf{3x + 24 = 4x}

Substract 3x to both sides

\mathsf{3x - 3x + 24 = 4x - 3x}

\mathsf{24 = 4x - 3x}

\large{\boxed{\mathsf{24 = x}}}

‎      ‏‏‎

<h3><u>Answer</u>. The value of x = 24.</h3>

‎      ‏‏‎

8 0
3 years ago
Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter tha
raketka [301]

According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

We assume the brightness of a dim day to be x.

According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.

Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.

According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.

Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.

Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.

Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.

Learn more about the developed scale at

brainly.com/question/4970963

#SPJ1

The question provided is incomplete. The complete question is:

"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?

Dim=2

Illuminated=3

Radiant=4

Dazzling=5"

8 0
1 year ago
Find the area of the rectangle is x² + 7x + 12. if its breadth is (x + 3), then find its length.​
miv72 [106K]

Answer:

the length.​ is : x+4

Step-by-step explanation:

x² + 7x + 12  = (x+3)(x+4)

the length.​ is : x+4

6 0
3 years ago
Read 2 more answers
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