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k0ka [10]
3 years ago
10

W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozos

tałej ilości. Resztę cukierków, w równych ilościach, kupiło trzech ostatnich klientów. Po ile cukierków czekoladowych dostali ostatni klienci?
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>

Step-by-step explanation:

The question is

<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>

<em />

Givens

  • The total amount of chocolate candies is 11.73 kilograms.
  • First costumer bought 48 dag of candies. (1 kg equals 100 dags)
  • Second costumer bougth 4/5 of the remaining.
  • Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

48dag \times \frac{1kg}{100dag}= 0.48 \ kg

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: 11.73kg-0.48kg=11.25kg

Now, we need to multiply the remaining amount of candies with 4/5

\frac{4}{5} \times 11.25kg=9 \ kg

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

11.25-9=2.25 \ kg

Therefore, the last costumers got 2.25 kilograms of chocolate candies.

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