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k0ka [10]
3 years ago
10

W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozos

tałej ilości. Resztę cukierków, w równych ilościach, kupiło trzech ostatnich klientów. Po ile cukierków czekoladowych dostali ostatni klienci?
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>

Step-by-step explanation:

The question is

<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>

<em />

Givens

  • The total amount of chocolate candies is 11.73 kilograms.
  • First costumer bought 48 dag of candies. (1 kg equals 100 dags)
  • Second costumer bougth 4/5 of the remaining.
  • Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

48dag \times \frac{1kg}{100dag}= 0.48 \ kg

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: 11.73kg-0.48kg=11.25kg

Now, we need to multiply the remaining amount of candies with 4/5

\frac{4}{5} \times 11.25kg=9 \ kg

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

11.25-9=2.25 \ kg

Therefore, the last costumers got 2.25 kilograms of chocolate candies.

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Answer:

Step-by-step explanation: Turn the mixed number into an improper fraction. -1 2/5 becomes -7/5.  To divide fractions, you keep the first fraction, change the division sign to mulitplication and flip the second fraction.  Then just multiply across the top and across the bottom. You will get 105/70.  Reduce by dividing both numerator and denomination by 35   Result will be 3/2.

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Find the coordinates of the transformed image when the pre-image is reflected over the line x=2
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8 0
3 years ago
Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

You have

..... | 2 ...  14  ... -58
-10 |    ... -20  ... 60
--------------------------
..... | 2 ...  -6  ....  2

So the quotient and remainder upon dividing is

\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}

with a remainder of 2, which means p(-10)=2.
5 0
3 years ago
Check my answer please? I'll report if you just say yeah and it's not correct lol.
Elena-2011 [213]
Yes, set up your proportion: x/21 = 10/14
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3 years ago
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