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k0ka [10]
3 years ago
10

W sklepie spożywczym jest 11,73 kg cukierków czekoladowych. Pierwszy klient kupił 48 dag cukierków. Drugi klient kupił 4/5 pozos

tałej ilości. Resztę cukierków, w równych ilościach, kupiło trzech ostatnich klientów. Po ile cukierków czekoladowych dostali ostatni klienci?
Mathematics
1 answer:
Elenna [48]3 years ago
4 0

Answer:

<h2>The last costumers got 2.25 kilograms of chocolate candies.</h2>

Step-by-step explanation:

The question is

<em> There is 11.73 kg of chocolate candies in the grocery store. The first customer bought 48 dag of candies. A second customer bought 4/5 of the remaining quantity. The last three customers bought the same amount of candy. How much chocolate did the last customers get?</em>

<em />

Givens

  • The total amount of chocolate candies is 11.73 kilograms.
  • First costumer bought 48 dag of candies. (1 kg equals 100 dags)
  • Second costumer bougth 4/5 of the remaining.
  • Another three costumers bought the same amount of candy.

Let's transform 48 dag to kilograms.

48dag \times \frac{1kg}{100dag}= 0.48 \ kg

Therefore, the first costumer bought 0.48 kilograms of candies.

The remaining amount is: 11.73kg-0.48kg=11.25kg

Now, we need to multiply the remaining amount of candies with 4/5

\frac{4}{5} \times 11.25kg=9 \ kg

Therefore, the second costumer bought 9 kilograms of chocolate candies.

At last, we need to find the new remaining part of candies, which is

11.25-9=2.25 \ kg

Therefore, the last costumers got 2.25 kilograms of chocolate candies.

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Which of the following equations is in equation formed when completing the square on y^2 - 12 y= -27
bogdanovich [222]

Answer:

(y-6)^2=9

Step-by-step explanation:

Given

y^2 - 12y = -27

Required

Get equivalent expression using completing the square

<em>Follow these steps:</em>

  • <em>Take the coefficient of y; That is -12</em>
  • <em>Divide it by 2; That is (-12/2)</em>
  • <em>Square it: (-12/2)^2</em>

<em />

Add to both sides of the equation

y^2 - 12y + (\frac{-12}{2})^2= -27 + (\frac{-12}{2})^2

y^2 - 12y + (-6)^2= -27 + (-6)^2

y^2 - 12y + 36= -27 + 36

y^2 - 12y + 36= 9

Expand the right-hand side

y^2 - 6y - 6y + 36= 9

Factorize:

y(y-6)-6(y-6) =9

(y-6)(y-6)=9

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5 0
3 years ago
PLEASE HELP ME!!
Grace [21]
Take the derivative:
g’(x) = 12x^3 - 24x^2

Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)

x = 0 or x = 2

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g(0) = 3(0^4) - 8(0^3)
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g(0) = 0

g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
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3 years ago
An ANOVA procedure is used for data that were obtained from four sample groups each comprised of five observations. The degrees
jeyben [28]

Answer:

(3,16)

Step-by-step explanation:

The degrees of freedom of the critical value F are (k-1,n-k).

We are given that there are four sample group, so,

k=4.

Also, we are given that the each four groups contains five observations, so,

n=4*5

n=20

The critical value F has degree of freedom

(k-1,n-k)

(4-1,20-4)

(3,16).

Thus, the degrees of freedom for the critical value of F are (3,16).

6 0
3 years ago
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Ne4ueva [31]
<h2>... Answer is in the pictures above... </h2><h3>... Hope this will help... </h3>

4 0
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saw5 [17]

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c.Right

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because of the 90 degrees it shows that it is 90 degrees

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