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Viktor [21]
3 years ago
6

Find the interest due on $1,200 at 8% for 240 days. (Remember that for bank interest purposes, a year is considered to have 360

days.)
Mathematics
2 answers:
alina1380 [7]3 years ago
4 0
I=1200*0.08*240/360
I==64
olga55 [171]3 years ago
4 0

Answer:  Interest is due is $64.

Step-by-step explanation:

Since we have give that

Principal = $1200

Rate of interest = 8%

Number of days = 240

As we know the formula for "Simple Interest":

Interest=\dfrac{P\times r\times t}{100}\\\\Interest=\dfrac{1200\times 8\times 240}{360\times 100}\\\\Interest=\$64

Hence, Interest is due is $64.

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Find the missing number of each unit rate. 18/3= ?/1 and 12/2= ?/1
gtnhenbr [62]

the answer is 6/1 and 6/1 simply divide and put the answer over one                      

3 0
3 years ago
A college has a 30% completion rate, meaning that 30% of all students who start at the college complete the goal they set. The p
RSB [31]

Answer:

45%

Step-by-step explanation:

For simplicity, let use assume there are 100 students in the school.

No. of students to complete college = (30/100) x 100 = 30 Students

President wants to increase by 50% = (50/100) x 30 = 15 Students

New set goal = 30 + 15 = 45 students.

Total number of students = 100 students

Therefore;

Rate goal % = (45/100) x 100% = 45%

4 0
3 years ago
What would be the dimensions for the poster at 1/4 times it’s current size
iVinArrow [24]

Answer:

D. Length = 9 cm; width = 6 cm

Step-by-step explanation:

Find 1/4 of the length and 1/4 of the width.

1/4 * 36 cm = 9 cm

1/4 * 24 cm = 6 cm

Answer: D. Length = 9 cm; width = 6 cm

6 0
3 years ago
(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0
3 years ago
Read 2 more answers
For which function is 5 NOT an element of the range?
Darina [25.2K]
B. y = -2 + 4
y = 2 not 5
5 0
3 years ago
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