Answer:
The system of linear equations are
and 
Step-by-step explanation:
Given : The number of students who chose lunch was 5 more than the number of students who chose breakfast. Let x represent the number of students who chose breakfast and y represent the number of students who chose lunch.
(50 students picked, 25 picked dinner the rest picked lunch and breakfast)
To find : Write a system of linear equations that represents the numbers of students who chose breakfast and lunch ?
Solution :
The number of students who chose breakfast be 'x'
The number of students who chose lunch be 'y'.
The number of students who chose lunch was 5 more than the number of students who chose breakfast.
i.e. 
Now, Total student were 50 and 25 picked dinner the rest picked lunch and breakfast i.e. 25.
So, 
Therefore, the system of linear equations are
and 
Answer: y=-(1/8)x+(21/2)
Explanation:
The new equation’s slope needs to be perpendicular to y=8x-1
To get the new slope, we take the negative reciprocal of the slope from above
8 —> -1/8
Now we have y=-(1/8)x+b but it needs to pass through (4,10), so we need to find the value of b that makes this possible.
Since (4,10) is in the form of (x,y) we can plug in these values into the new equation to solve for b:
y=-(1/8)x+b
10=-(1/8)4+b
10=(-1/2)+b
b=(21/2)
Now put b back into the new equation
y=-(1/8)x+b
y=-(1/8)x+(21/2)
Answer:
49
Step-by-step explanation:
-11 2/3 x (-4 1/5) =
negative times negative = positive
Change the mixed numerals into fractions.
= 35/3 × 21/5
Multiply the numerators together. Multiply the denominators together.
= (35 × 21)/(3 × 5)
Simplify.
= (7 × 5 × 7 × 3)/(3 × 5)
Divide the numerator and denominator by 3 and by 5.
= 7 × 7
= 49