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Mariulka [41]
3 years ago
5

A motorcycle average 23 miles per gallon. If gas is currently 2.35 per gallon, how much would be spent in gas if the motorcycle

were to travel 220 miles?
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

Gallons of gas needed = 220/23 = 9.565 gallons

Amount of money spent on gas = $2.35 x 9.565 = $22.48

Step-by-step explanation:

lara [203]3 years ago
5 0
Gallons of gas needed = 220/23 = 9.565 gallons
Amount of money spent on gas = $2.35 x 9.565 = $22.48
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Step-by-step explanation:

26+35+41+ 18 = 120

120/24 = 5

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5 (5x6)+(8x9)+6=? 2(5x8)+(8x28)+9
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On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3,
nikitadnepr [17]

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(0, -9)

Step-by-step explanation:

On a coordinate plane, a curved line with a minimum value of (0, negative 9) and maximum values of (negative 2.3, 16) and (2.3, 16), crosses the x-axis at (negative 3, 0), (negative 1, 0), (1, 0), and (3, 0), and crosses the y-axis at (0, negative 9). Which is a y-intercept of the graphed function? (–9, 0) (–3, 0) (0, –9) (0, –3)

The y-intercept is the point where x = 0, and It says there that the graph crosses the y-axis at (0, -9)

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You ran 800 meters in 5 minutes what your average speed
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160 metres per minute

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7.109) The leading brand of dishwasher detergent has a 30% market share. A sample of 25 dishwasher detergent customers was taken
Rina8888 [55]

Answer:

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they choose the leading brand, or they do not. The probability of a customer choosing the leading brand is independent of any other customer, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The leading brand of dishwasher detergent has a 30% market share.

This means that p = 0.3

A sample of 25 dishwasher detergent customers was taken.

This means that n = 25

a. What is the probability that 10 or fewer customers choose the leading brand?

This is:

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{25,0}.(0.3)^{0}.(0.7)^{25} = 0.0001

P(X = 1) = C_{25,1}.(0.3)^{1}.(0.7)^{24} = 0.0014

P(X = 2) = C_{25,2}.(0.3)^{2}.(0.7)^{23} = 0.0074

P(X = 3) = C_{25,3}.(0.3)^{3}.(0.7)^{22} = 0.0243

P(X = 4) = C_{25,4}.(0.3)^{4}.(0.7)^{21} = 0.0572

P(X = 5) = C_{25,5}.(0.3)^{5}.(0.7)^{20} = 0.1030

P(X = 6) = C_{25,6}.(0.3)^{6}.(0.7)^{19} = 0.1472

P(X = 7) = C_{25,7}.(0.3)^{7}.(0.7)^{18} = 0.1712

P(X = 8) = C_{25,8}.(0.3)^{8}.(0.7)^{17} = 0.1651

P(X = 9) = C_{25,9}.(0.3)^{9}.(0.7)^{16} = 0.1336

P(X = 10) = C_{25,10}.(0.3)^{10}.(0.7)^{15} = 0.0916

Then

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0001 + 0.0014 + 0.0074 + 0.0243 + 0.0572 + 0.1030 + 0.1472 + 0.1712 + 0.1651 + 0.1336 + 0.0916 = 0.9021

0.9021 = 90.21% probability that 10 or fewer customers choose the leading brand

3 0
3 years ago
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