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Assoli18 [71]
3 years ago
9

What is the area of the blue shaded region ?​please help

Mathematics
1 answer:
pshichka [43]3 years ago
6 0

Answer:

125.66

Step-by-step explanation:

11cm squared times pi =380.13

9cm squared times pi =254.47

380.13-254.47=125.66

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Take away 9 from 4 times y
Gala2k [10]
4y-9 is the answer.
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3 years ago
Use the function f(x) to answer the questions: f(x) = 2x2 − x − 10
Sidana [21]

Answer:

A. x = -2, 5/2

B. Minimum

Vertex: (1/4, -81/8)

C. Draw a concave up graph connecting the x-intercepts, vertex and the y-intercept

Step-by-step explanation:

f(x) = 2x² - x - 10

2x² - x - 10 = 0

2x² - 5x + 4x - 10 = 0

x(2x - 5) + 2(2x - 5) = 0

(x + 2)(2x - 5) = 0

x = -2, 5/2

Vertex: (h,k)

h = midpoint of the x-intercepts (due to symmetry)

h = (-2 + 5/2) = 1/4

k = f(1/4)

k = 2(1/4)² - 1/4 - 10 = -81/8

Vertex: (1/4, -81/8)

y-intercept: when x = 0

2(0)² - 0 - 10 = -10

Draw a concave up quadratic connecting thr following points:

(-2,0)

(0,-10)

(1/4,-81/4)

(5/2,0)

6 0
4 years ago
a bakery used 25% more butter this month than last month. if the bakery used 240 kilograms of butter last month, him much did it
Neko [114]

Answer:

600 i think that's what the calculator said .

Step-by-step explanation:

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3 years ago
April decided to purchase
Soloha48 [4]

Answer:

milk?

Step-by-step explanation:

7 0
3 years ago
21.4.4 Quiz: Normal Curves
zaharov [31]

Using the Empirical Rule, approximately 95% of the area under the whole curve is in the two tails.

<h3>What does the Empirical Rule state?</h3>

It states that, for a normally distributed random variable:

  • Approximately 68% of the measures are within 1 standard deviation of the mean.
  • Approximately 95% of the measures are within 2 standard deviations of  the mean.
  • Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Hence, approximately 95% of the area under the whole curve is in the two tails.

More can be learned about the Empirical Rule at brainly.com/question/24537145

#SPJ1

7 0
2 years ago
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