Michael is doing an underwater handstand. His feet are sticking up 0.5 0.50, point, 5 meters above the surface of the water. Mic
1 answer:
Answer:
The position of Michael's hands relative to the surface of the water is -<u>1.3 meters</u>.
Step-by-step explanation:
<u><em>The question is incomplete, so below is the complete question?</em></u>
<em>Michael is doing an underwater handstand. His feet are sticking up 0.5 meters above the surface of the water. Michael's hands are 1.8 meters directly below his feet. What is the position of Michael's hands relative to the surface of the water?</em>
Now, to find the position of Michael's hands relative to the surface of the water.
Meters of Michael's hands directly below his feet = 1.8 meters.
Meters of his feet sticking above the surface of the water = 0.5 meters.
So, to get the position of Michael's hands relative to the surface of the water we subtract meters of Michael's hands directly below his feet from meters of his feet sticking above the surface of the water:
Therefore, the position of Michael's hands relative to the surface of the water is -1.3 meters.
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Answer:
$712.
Step-by-step explanation:
We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.
We will use compound interest formula to solve our given problem.
, where,
A = Final amount,
P = Principal amount,
r = Annual interest rate in decimal form,
n = Number of times interest is compounded per year,
t = Time in years.
Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.
Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.