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3 years ago

Which expression can be used to find the product of 98 x 34?

Mathematics

1 answer:

sergejj [24]3 years ago

6 0

Answer:

The Second One.

Step-by-step explanation:

(90 x 30) + (90 x 4) + (8 x 30) + (8 x 4)

This One simply Goes to the expression that (90*34)+(8*34)=(34)*(90+4) = (94*34)

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9. In a school, there are 120 students in a particular year group. Out of those students, 100 study

Tresset [83]

This does not make any sense I don’t know how to help you out sorry

6 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

3 years ago

Serena wants to solve the following system of equations in the most efficient way.

Marianna [84]

Answer:

Serina should have solved for x in the second equation because it has a coefficient of 1.

Step-by-step explanation:

we have

$2x+3y=18$ ----> equation A

$x+7y=31$ ---> equation B

we know that

To solve the system of equations in the most efficient way, solve for x equation B and then substitute the value of x in equation A

$x=31-7y$ ----> equation C

substitute equation C in equation A

$2(31-7y)+3y=18$

solve for y

$62-14y+3y=18\\11y=62-18\\11y=44\\y=4$

Find the value of x

substitute the value of y in the equation C

$x=31-7(4)=3$

The solution is (3,4)

therefore

Serina should have solved for x in the second equation because it has a coefficient of 1.

3 0

3 years ago

Read 2 more answers

I really suck at math. please help =)

FrozenT [24]

Check the picture below.

6 0

4 years ago

Help guys with the question

Naya [18.7K]

Answer:

$\sin\Big(\dfrac{\theta }{2}\Big) = \dfrac{2\sqrt 5}{5}$

Step-by-step explanation:

$\cos(2x) = \cos^2 x-\sin^2 x = 1-2\sin^2 x \\ \\ \cos(x) = 1-2\sin^2 (\frac{x}{2}) \\ \\ \Rightarrow \sin^2 (\frac{x}{2}) = \dfrac{1-\cos(x)}{2}\\ \\ \sin(\frac{x}{2}) = \pm \sqrt{\dfrac{1-\cos(x)}{2}},\quad x\in [\frac{3\pi }{2},\pi] \Rightarrow \frac{x}{2}\in [\frac{3\pi}{4},\frac{\pi}{2}]\\ \\ \Rightarrow \sin(\frac{x}{2}) > 0 \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{1-(-\frac{3}{5})}{2}} \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{8}{10}}=\dfrac{2\sqrt 2}{\sqrt{10}} = \\ \\ =\dfrac{2\sqrt 5}{5}$

7 0

3 years ago