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Flura [38]
3 years ago
8

How do I solve this using elimination

Mathematics
1 answer:
monitta3 years ago
3 0

There are a number of ways you can solve this using elmination. The basic idea is to multiply one or both of the equations by something so that the coefficients of one of the variables is the same or opposite in the two resulting equations.

Here, this could mean you multiply the second equation by 2 to make the y-coefficient -2, which is the opposite of the y-coefficient in the first equation, 2.

I like better the idea of dividing the first equation by 2. This also makes the y-coefficient the opposite of its value in the second equation. Now, your equations are

2x+y=5\\x-y=13

Adding these two equations gives

(2x+y)\,+\,(x-y)=(5)\,+\,(13)\\3x=18\qquad\text{notice y terms have been eliminated}\\\\x=6

The second equation can be rearranged to tell you

... y = x - 13

so, for x=6, this gives

... y = 6 - 13 = -7

Your solution is (x, y) = (6, -7).

_____

Since we used the second equation to get the value of y from x, we know these values satisfy that one. We can check them in the first equation:

... 4·6 + 2·(-7) = 24 - 14 = 10 . . . . . values also satisfy the first equation

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STatiana [176]

Answer:

2⁶

Step-by-step explanation:

Rule of exponents, if you multiply number with the same base, you add the exponents

- Gage Millar, Algebra 2 tutor

3 0
3 years ago
The distribution of 4 in the following expression (5+s)4
ruslelena [56]

Answer:

( 5 + s ) 4 = 20 + 4 s

Step-by-step explanation:

<u><em>Distribution property</em></u>

Let a, b and c are numbers then distribution property is defined by

a( b + c) = a b + a c

(a+ b) c = a c + b c

Given that

( 5 + s ) 4 = 5× 4 + s× 4

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<u><em>Final answer:-</em></u>

( 5 + s ) 4 = 20 + 4 s

6 0
3 years ago
Y= 2x^3 - 15x^2 + 36x - 20 find turning points and show working out
Murljashka [212]

Given:

The function is:

y=2x^3-15x^2+36x-20

To find:

The turning points.

Solution:

We have,

y=2x^3-15x^2+36x-20

Differentiate the given function with respect to x.

y'=2(3x^2)-15(2x)+36(1)-(0)

y'=6x^2-30x+36

y'=6(x^2-5x+6)

For turning point, y'=0.

6(x^2-5x+6)=0

x^2-3x-2x+6=0

x(x-3)-2(x-3)=0

(x-3)(x-2)=0

Using zero product property, we get

x-3=0 and x-2=0

x=3 and x=2

Therefore, the turning points of the given function are at x=2 and x=3.

8 0
3 years ago
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AleksandrR [38]

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Step-by-step explanation:

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180-100=80

8 0
3 years ago
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baherus [9]

Answer:

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Step-by-step explanation:

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