5,918 divided by 65 plz plz show work

HELP ME PLEASE!! NO FAKE ANSWERS PLEASE!! :D ILL GIVE BRAINILEST FOR THE CORRECT ANSWER!!!!

viva [34]

Answer:

x=20

Step-by-step explanation:

It all equals 360º and there are two of each angle. So, we can add 5x+5x+(3x+20)+(3x+20)=360º. Subtracted 40 and simplify. So 16x=320.So divide by 16 and you get that x=20.

4 0

3 years ago

Plot the points −4.5 and 2.5 on the number line. Then use the number line to find the distance between the two points. Show all

EastWind [94]

Answer:7

Step-by-step explanation:

from -4.5 to 0 is 4.5

from 0 to 2.5 is 2.5

4.5 +2.5=7

8 0

3 years ago

Find the solution set of the absolute value equation: |2x−6|+4=20

vekshin1

$|2x - 6| = 16 \\ 2x - 6 = 16 > > > x = \frac{22}{2} = 11 \\ 2x - 6 = - 16 > > x = - 5$

6 0

3 years ago

Help on 7 and 8b please and thank you.

andreev551 [17]

7)
$total \: increase \: for \:sides \: of \: the \: equillateral \: triangle = 3 \times 5cm = 15cm \\ perimeter \: of \: an \: equillateral \: triangle = 3 \times length \: of \: one \: side \\ originl \: perimeter = incresed \: perimeter - increase = 60cm - 15cm = 45cm \\ one \: side \: of \: the \: equillateral \: triangle = 45cm \div 3 = 15cm$
8b)
$let \: x \: represent \: the \: amount \: each \: person \: has \: in \: the \: end. \\ 40 - 4(7.50) = 4x \\ 40 - 30 = 4x \\ 10 = 4x \\ 4x = 10 \\ x = 10 \div 4 \\ x = 2.5 \\ each \: boy \: has \: 2.50 \: in \: the \: end$

8 0

4 years ago

In a survey, 32% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result

adoni [48]

Answer:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

$\hat p=\frac{61}{210}=0.29$ estimated proportion of pet owners contacted by telephone

$p_o=0.32$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:

Null hypothesis: $p \geq 0.32$

Alternative hypothesis: $p < 0.32$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

3 0

3 years ago