Uh im not sure completely but ill try my best to help.
f(x)=x-16/(x+10)(x-4)
g(x)=1/x+10
Now find a common denominator. (x+10)(x-4) is a good one.
x-16/(x+10)(x-4)+x-4/(x+10)(x-4)
2x-20/(x+10)(x-4)
So I think the answer is 2(x-10)/(x+10)(x-4) and x≠-10 and x≠4
Thats the most you can factor it. Don’t try to cancel out the (x-10) and the (x+10)
Brainliest my answer if it helped you out?
Given:
The figure of a triangle LMN.
P is the centroid of triangle LMN.
To find:
14. Find the value of PN if QN=30.
15. Find the value of PN if QN=9.
Solution:
We know that the centroid in the intersection of medians of a triangle and centroid divides each median in 2:1.
Since P is the centroid it means NQ is the median from vertex N. It means P divides the median NQ in 2:1. So, PN:PQ=2:1.
14. We have QN=30.




Therefore, the value of PN is 20 when QN=30.
15. We have QN=9.




Therefore, the value of PN is 6 when QN=9.
Answer:
question number 2 is correct
question number 3 is incorrect the answer is 89
question number 4 is correct
question number 5 is incorrect the answer is 31
question number 6 is correct
The best way to do this question is to use elimination. Elimination is a way to find out the POINT OF INTERSECTION between two lines. Let me show you how.
3y+4x=3
x+3y=-6
Elimination is a way to remove any same variable with the same coefficient. In this case, there is 3y in both equations. In this case, we subtract to eliminate.
3y-3y+4x-x=3+6 It's plus 6 because two negatives become positive.
3x=9 Divide both sides by 3
x=3
Now you can find y.
x+3y=-6
3+3y=-6
3y=-9
y=-3
Therefore, the POI is (3,-3). I hope you understand this. Make sure to mark as brainliest.
The question is also the same as asking what is the x value of the solution of the two functions graphed above. The solution is the point where these lines intersect. So, from the choices, the correct answer would be the second option. The input value that <span>produces the same output value for the two functions on the graph would be x=-2. Hope this answers the question.</span>